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Natali [406]
3 years ago
14

Help please help please help do

Chemistry
1 answer:
Yanka [14]3 years ago
3 0
For the first two
1. Will only give up one atom to be stable
2. Only 2 atoms
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Calcium Carbonate decomposes at 1200°C to form carbon dioxide and
Travka [436]

This is a Charles' Law problem: V1/T1 = V2/T2. As the temperature of a fixed mass of gas decreases at a constant pressure, the volume of the gas should also decrease proportionally.

To use Charles' Law, the temperature must be in Kelvin (x °C = x + 273.15 K). We want to solve Charles' Law for V2, which we can obtain by rearranging the equation into V2 = V1T2/T1. Given V1 = 25 L, T1 = 1200 °C (1473.15 K), and T2 = 25 °C (298.15 K):

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5 0
3 years ago
PLEASE HELP ASAP. I WILL MARK BRAINLIEST!!!
iris [78.8K]

I Cant Answer your question but maybe this will help

Volume Changes for Gases

Particles in a gas have more freedom of movement than they do in a liquid. According to the ideal gas law, the pressure (P) and volume (V) of a gas are mutually dependent on temperature (T) and the number of moles of gas present (n). The ideal gas equation is PV = nRT, where R is a constant known as the ideal gas constant. In SI (metric) units, the value of this constant is 8.314 joules ÷ mole - degree K.

Pressure is constant: Rearranging this equation to isolate volume, you get: V = nRT ÷ P, and if you keep the pressure and number of moles constant, you have a direct relationship between volume and temperature: ∆V = nR∆T ÷ P, where ∆V is change in volume and ∆T is change in temperature. If you start from an initial temperature T0 and pressure V0 and want to know the volume at a new temperature T1 the equation becomes:

V1 = [n • R • (T1 - T0) ÷ P] +V0

Temperature is constant: If you keep the temperature constant and allow pressure to change, this equation gives you a direct relationship between volume and pressure:

V1 = [n • R • T ÷ (P1 - P0)] + V0

Notice that the volume is larger if T1 is larger than T0 but smaller if P1 is larger than P0.

Pressure and temperature both vary: When both temperature and pressure vary, the the equation becomes:

V1 = n • R • (T1 - T0) ÷ (P1 - P0) + V0

Plug in the values for initial and final temperature and pressure and the value for initial volume to find the new volume.

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