The strong nuclear force is always smaller than the electrostatic force true or false

Chemistry

2 answers:

emmasim [6.3K]3 years ago

5 0

Answer:

False

Explanation:

The Strong Nuclear Force is defined as an attractive force between neutrons and protons which is responsible to hold the nucleus together.

Electrostatic force is the repulsive or attractive force between two electrically charged objects.

Strong nuclear force is always greater than electrostatic force but changes with the distance. Strong nuclear attraction keeps the nucleus of an atom together in a small space as well which is stronger than their electrostatic repulsion.

it is said that, the strong nuclear force is the strongest force in the universe.

Hence, the given statement is false.

IrinaK [193]3 years ago

3 0

Answer:

False

Explanation:

Strong nuclear forces are much higher than the electrostatic repulsive force. In case if these strong nuclear forces would have not been there, then the nucleus would have disintegrated. This is so because only gravity cannot keep hold on these particles. The nuclear force varies with the size of nucleus. As the size of nucleus increases, the electrostatic repulsion becomes greater

Hence, the given statement is false

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Calculation: If a compound is 14.40% hydrogen by mass and 85.60% carbon by mass, what is the empirical formula?

IgorLugansk [536]

Answer:

CH2

Explanation:

We are given that a compound is 14.40% hydrogen and 85.60% carbon.

Let the mass of the substance be 100g.

Mass of the hydrogen: 14.40% of 100 = 14.40 g

Mass of the carbon: 85.60% of 100 = 85.60 g

Now, let's find the moles of hydrogen:

$14.40 g*\frac{1 mole}{1gH} = 14.40 mole$

Moles of carbon:

$85.60g*\frac{1 mol}{12gC} = 7.13mol$

Let's put these in a ratio and simplify:

7.13 mole C: 14.40 mole H

1 mole C: 2 mole H

Therefore, the empirical formula of this compound is CH2.

Hope this helps!! If you have any questions about my work, please let me know in the comments!

3 0

2 years ago

Consider a mixture of two gases, A and B, confined in a closed vessel. A quantity of a third gas, C, is added to the same vessel

n200080 [17]

The question is incomplete, here is the complete question:

Consider a mixture of two gases, A and B, confined in a closed vessel. A quantity of a third gas, C, is added to the same vessel at the same temperature. How does the addition of gas C affect the following. The mole fraction of gas B?

A mixture of gases contains 10.25 g of N₂, 2.05 g of H₂, and 7.63 g of NH₃.

Answer: The mole fraction of gas B (hydrogen gas) is 0.557

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)