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DaniilM [7]
3 years ago
7

A baseball is thrown into the air from a height of 5 feet. The ball reaches a maximum height of 43.5 feet and spends a total of

3.2 seconds in the air. Write the equation that models the height of the baseball? Assume that acceleration due to gravity is –16 ft/s2
Mathematics
2 answers:
maks197457 [2]3 years ago
5 0
H = 5 + ut - 16t^2
When the balls falls back to the ground, h = 0
0 = 5 + 3.2u - 16(3.2)^2
0 = 5 + 3.2u - 163.84
0 = 3.2u - 158.84
3.2u = 158.84
u = 158.84/3.2 = 49.6 ft/s

Required equation is
h = 5 + 49.6t - 16t^2
elena-s [515]3 years ago
5 0

The answer is C.. You're welcome

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If (a^x a ^y) - a^z = a^m then express m in terms of x, y and z.​
omeli [17]

Answer:

m = x+y-z

Step-by-step explanation:

Given the expression.

(a^x a ^y) ÷ a^z = a^m

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Using the multiplicative law of indices, the expression becomes:

a^{x+y} ÷ a^z = a^m

Applying the division rule in indices

a^{x+y} ÷ a^z = a^{x+y-z}

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a^{x+y-z} = a^m

Cancel out the base and equate the powers as shown:

x+y-z = m

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5 0
2 years ago
An employment agency specializing in temporary construction help pays heavy equipment operators
pochemuha
Answer:
Number of heavy equipment operators hired were 22
Number of general laborers hired were 11

Explanation:
Assume that number of heavy equipment operators hired is x and that number of general laborers is y.

We are given that:
1- Total number of hired people is 33. This means that:
x + y = 33
This can be rewritten as:
x = 33 - y ...........> equation I
2- heavy equipment operators are paid $135, general laborers are paid $89 and that the total payment was $3949. This means that:
135x + 89y = 3949 ............> equation II

Substitute with equation I in equation II and solve for y as follows:
135x + 89y = 3949
135(33-y) + 89y = 3949
4455 - 135y + 89y = 3949
506 = 46y
y = 506 / 46
y = 11

Substitute with y in equation I to get the value of x as follows:
x = 33 - y
x = 33 - 11
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Hope this helps :)
4 0
3 years ago
Read 2 more answers
Solve for x in the equation x^2-14+31=63
Bingel [31]
To solve for a variable, you need to get it (x) by itself.

x² - 14 + 31 = 63   Add 31 to -14
x² + 17 = 63   Subtract 17 from both sides of the equation
x² = 46   Square root both sides
x = \pm \sqrt{46}

Check your work by plugging in \sqrt{46} for x and then - \sqrt{46}.

\sqrt{46}² - 14 + 31 = 63   Square \sqrt{46}
46 - 14 + 31 = 63   Subtract 14 from 46
32 + 31 = 63   Add
63 = 63

- \sqrt{46}² - 14 + 31 = 63   Square - \sqrt{46}
46 - 14  + 31 = 63   Subtract 14 from 46
32 + 31 = 63   Add
63 = 63

So, x is \sqrt{46} and - \sqrt{46} .
3 0
3 years ago
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