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icang [17]
3 years ago
5

Geometry help needed!

Mathematics
1 answer:
salantis [7]3 years ago
3 0

Answer:

AC Midpoint (2,0)-

CB Midpoint (5,-4)

midlength is 5

Step-by-step explanation:

midpoint formula (\frac{x_{1}+x_{2}  }{2} ,\frac{y_{1} +y_{2} }{2})

A(2,4) C(2,-4)

\frac{2+2}{2} =\frac{4}{2}=2\\\frac{4-4}{2}  =\frac{0}{2} =0

(2,0)

C(2,-4) B(8,-4)

\frac{8+2}{2} =\frac{10}{2} =5

\frac{-4-4}{2} =\frac{-8}{2} =-4  midpoint is  (5,-4)

Distance between the 2 midpoints is the midsegment

(2,0) and (5,-4)

d=\sqrt{(x_{2}-x_{1})^{2} +(y_{2}-y_{1})  ^{2}   }

d=\sqrt{(5-2)^{2} +(-4-0)^{2}  } \\d=\sqrt{3^{2} +(-4^{2})\\ } \\d=\sqrt{x} 9+16\\d=\sqrt{25} \\d=5

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