Question

. A triangle has vertices on a coordinate grid at points J(-1, 5), K(4, 5), and L(4, -2). What is the length, in units, of ?

Answer 1

Answer:

20.6

Step-by-step explanation:

Given data

J(-1, 5)

K(4, 5), and

L(4, -2)

Required

The perimeter of the traingle

Let us find the distance between the vertices

J(-1, 5) amd

K(4, 5)

The expression for the distance between two coordinates is given as

d=√((x_2-x_1)²+(y_2-y_1)²)

substitute

d=√((4+1)²+(5-5)²)

d=√5²

d= √25

d= 5

Let us find the distance between the vertices

K(4, 5), and

L(4, -2)

The expression for the distance between two coordinates is given as

d=√((x_2-x_1)²+(y_2-y_1)²)

substitute

d=√((4-4)²+(-2-5)²)

d=√-7²

d= √49

d= 7

Let us find the distance between the vertices

L(4, -2) and

J(-1, 5)

The expression for the distance between two coordinates is given as

d=√((x_2-x_1)²+(y_2-y_1)²)

substitute

d=√((-1-4)²+(5+2)²)

d=√-5²+7²

d= √25+49

d=  √74

d=8.6

Hence the total length of the triangle is

=5+7+8.6

=20.6