. A triangle has vertices on a coordinate grid at points J(-1, 5), K(4, 5), and L(4, -2). What is the length, in units, of ?
1 answer:
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Solution (1)
for k=0 / for k=1 / for k=-1
x=0 / x=2π / x=-2π
acc / acc / rej
solution (2)
for k=0 / for k=1 / for k=-1
x=0 / x=2π/3 / x=-2π/3
acc / acc / rej
Note that i'm trying values of K which make the answer belong to our interval;
So our solution which i will represent as a set is;
S € {0,2π/3,2π}
Answer:
a(+
) = = -13
Step-by-step explanation:
Given that a = -1, b=2 and c= -3
find the value of a(+
)
Just substitute the values given for each variable
a(+
) = (-1)(
+
) ; do the exponents first
a(+
) = (-1)(4+9)=(-1)(13) ; now add inside the parenthesis;
a(+
) = -13 ; and multiply by -1