Answer:
(0,3), (4, -1)
Step-by-step explanation:
we have
![y=-x+3](https://tex.z-dn.net/?f=y%3D-x%2B3)
This is a linear equation (The graph is a line)
we know that
If a ordered pair is on the graph of the line, then the ordered pair must satisfy the equation of the line
<u><em>Verify each case</em></u>
case 1) (1, 2), (0, -3)
<em>First point</em>
x=1,y=2
substitute in the equation and then compare the result
![2=-1+3](https://tex.z-dn.net/?f=2%3D-1%2B3)
---> is true
so
The first point is on the graph
<em>Second point</em>
x=0,y=-3
substitute in the equation and then compare the result
![-3=-0+3](https://tex.z-dn.net/?f=-3%3D-0%2B3)
---> is not true
so
The second point is not on the graph
therefore
The two points are not on the graph
case 2) (0,3), (4, -1)
<em>First point</em>
x=0,y=3
substitute in the equation and then compare the result
![3=0+3](https://tex.z-dn.net/?f=3%3D0%2B3)
---> is true
so
The first point is on the graph
<em>Second point</em>
x=4,y=-1
substitute in the equation and then compare the result
![-1=-4+3](https://tex.z-dn.net/?f=-1%3D-4%2B3)
---> is true
so
The second point is on the graph
therefore
The two points are on the graph
case 3) (-1, -2), (1,4)
<em>First point</em>
x=-1,y=-2
substitute in the equation and then compare the result
![-2=-(-1)+3](https://tex.z-dn.net/?f=-2%3D-%28-1%29%2B3)
---> is not true
so
The first point is not on the graph
therefore
The two points are not on the graph
case 4) (4, -1), (1,3)
<em>First point</em>
x=4,y=-1
substitute in the equation and then compare the result
![-1=-4+3](https://tex.z-dn.net/?f=-1%3D-4%2B3)
---> is true
so
The first point is on the graph
<em>Second point</em>
x=1,y=3
substitute in the equation and then compare the result
![3=-1+3](https://tex.z-dn.net/?f=3%3D-1%2B3)
---> is not true
so
The second point is not on the graph
therefore
The two points are not on the graph