We want double sixes. This means that we want both the first roll and the second roll to be 6.
The given point is given as (r1 , r2) where:
r1 is output from first roll
r2 is output from second roll
Since we want both outputs to be 6, therefore, the answer would be: (6,6)
Answer:
he is three i think
Step-by-step explanation:
Answer:
r(A + B) = rA + rB,. (4). (r + s)A = rA + sA,. (5) r(sA)=(rs)A;. (6). A(BC)=(AB)C,.
First, let's break the worded equation up into two parts:
- "<span>4 times a number less than 6'
This is 4 * (6-x)
- "</span><span>8 more than twice that number"
This is 2x+8
Now combine these two expressions:
</span>4 * (6-x) = 2x+8
4 * (6-x) = 2 * (x+4)
2 * (6-x) = x+4
12-2x = x+4
-3x = -8
x = 8/3
If you have any questions, please leave it in the comment section below.
Hope this helps!
The solution is the point where the lines meet.
The x coordinate is between 0 and 1
The y coordinate is between 2 and 3
The solution is approximately (x,y) = (-0.4, 2.9)
