(1/2)/2=3/x
we can cross multiply, aka multiply both sides by 2x
(1/2)x=2*3
(1/2)x=6
times 2/1 both sides
x=12
Answer:
Divide both sides by -1/3, Apply distributive property, add 1/3 to both sides
Step-by-step explanation:
If its confusing just replace -1/3 with a simple number such as -1, to make it make sense.
Answer:
The standard form is 8 y ⁵ - 17 y⁴ + 6 y³ +2 y² - 11
The degree of given polynomial is '5'
the co-efficient of y⁴ is '-17'
Step-by-step explanation:
Given standard form 2 y²+ 6 y³-11-17 y⁴+8 y⁵
<em>The form ax² + b x + c is called the standard form of the quadratic expression of 'x'.This is second degree standard form of polynomial.</em>
<em>The form ax⁵ + b x⁴ + c x³ +d x² +ex +f is called the standard form of the quadratic expression of 'x'.This is fifth degree standard form of polynomial</em>
now Given polynomial is 2 y²+ 6 y³-11-17 y⁴+8 y⁵
The standard form is
8 y ⁵ - 17 y⁴ + 6 y³ +2 y² - 11
<u><em>Conclusion</em></u>:-
<em>The degree of given polynomial is '5'</em>
<em>The co-efficient of y⁴ is '-17'</em>
<em> </em>
Answer:
The sum of the first 6 terms is 3,412.5.
Step-by-step explanation:
The second term of the geometric series is given by:
Where a1 is the first term and r is the common ratio. The seventh term can be written as a function of the second term as follows:
![a_{7}=a_{1}*r^{6} \\a_{7}=a_{2}*r^{5} \\10,240 = 10*r^{5}\\r=\sqrt[5]{1024} \\r = 4](https://tex.z-dn.net/?f=a_%7B7%7D%3Da_%7B1%7D%2Ar%5E%7B6%7D%20%5C%5Ca_%7B7%7D%3Da_%7B2%7D%2Ar%5E%7B5%7D%20%5C%5C10%2C240%20%3D%2010%2Ar%5E%7B5%7D%5C%5Cr%3D%5Csqrt%5B5%5D%7B1024%7D%20%5C%5Cr%20%3D%204)
The sum of "n" terms of a geometric series is given by:
The sum of the first 6 terms is 3,412.5.
