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gregori [183]
3 years ago
6

Jeanne makes hair bows to sell at the craft fair. Each bow requires 1.5 yards of ribbon.

Mathematics
1 answer:
UkoKoshka [18]3 years ago
8 0

Answer:

a) 378 foot

b) 3780¢

c)10^3\times 2^1\times 3^3\times 7^1

Step-by-step explanation:

Given: Ribbon required to make 1 bow = 1.5 yards

We know that 1 yard = 3 foot

a) Number of bows Jeanne wants to make = 84

Foot of ribbon required to make 84 bows

= Number of bows Jeanne wants to make × Ribbon required to male 1 bow

= 84 × 1.5 yards

= 126 × 3 foot = 378 foot

Thus, Jeanne requires 378 foot of ribbon to make 84 bows.

b) Cost of ribbon = 10¢ per foot

Total money required to buy ribbon

= Cost of ribbon × Amount of ribbon required in foot

= 10 × 378

= 3780.00¢

c) Number of bows manufacture wants to make = 84 × 1000

= 84,000 bows

Amount of ribbon required to make bows

= 1000 × Amount of ribbon required to make 84 bows

=  1,000 × 378 = 378000 foot

To write it in exponential form:

378000 = 10^3\times 2^1\times 3^3\times 7^1

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AnnZ [28]
Well, the answer quite simple ....there are 4! ways to arrange these numbers...and as 4! = 4*3*2*1 = 24

hence 24 is the correct answer....


u can also remember it by theorem of multiplication as.....in first place (I.e. first code can be any no. out of 4,5,2&7 ....so 4*.....

as first place is acquired by a certain no. that leaves three no. to fill third place and when third place I'd occupied it leaves 2 numbers to fill second place and lastly only one no. to fill the last place .....so it's result will be like 4*3*2*1.



I know this is pretty much confusing ....but still I tried my best....

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3 years ago
Algebra 2- Common Functions PLEASE HELP!
RoseWind [281]

Answer: B

Step-by-step explanation:

Intersection of the 2 parts of the function is (0,0):

==> not A

the second part of the function is an half-line (and x =0)

Answer B

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Let C be the first quadrant portion of the circle of radius 3 centered on the origin. Find the line itegral for x^2+y^2 over C.
egoroff_w [7]
YX equals +2 squared minus -17 is approximately the answer of the origin
7 0
3 years ago
3 2/3 - 2 3/4= ______________
NISA [10]

Answer:

7  5/12

Step-by-step explanation:

3+2=6

2/3 + 3/4 = 8/12 + 9/12 = 17/12 = 1   5/12

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7 0
3 years ago
Read 2 more answers
which expressions are equivalent to the first one? I don't understand how to determine that so please explain. Thanks!​
coldgirl [10]

9514 1404 393

Answer:

  (a) -(x+7)/y

  (b) (x+7)/-y

Step-by-step explanation:

There are several ways you can show expressions are equivalent. Perhaps the easiest and best is to put them in the same form. For an expression such as this, I prefer the form of answer (a), where the minus sign is factored out and the numerator and denominator have positive coefficients.

The given expression with -1 factored out is ...

  \dfrac{-x-7}{y}=\dfrac{1(x+7)}{y}=\boxed{-\dfrac{x+7}{y}} \quad\text{matches A}

Likewise, the expression of (b) with the minus sign factored out is ...

  \dfrac{x+7}{-y}=\boxed{-\dfrac{x+7}{y}}

On the other hand, simplifying expression (c) gives something different.

  \dfrac{-x-7}{-y}=\dfrac{-(x+7)}{-(y)}=\dfrac{x+7}{y} \qquad\text{opposite the given expression}

__

Another way you can write the expression is term-by-term with the terms in alpha-numeric sequence (so they're more easily compared).

  Given: (-x-7)/y = (-x/y) +(-7/y)

  (a) -(x+7)/y = (-x/y) +(-7/y)

  (b) (x+7)/(-y) = (-x/y) +(-7/y)

  (c) (-x-7)/(-y) = (x/y) +(7/y) . . . . not the same.

__

Of course, you need to know the use of the distributive property and the rules of signs.

  a(b+c) = ab +ac

  -a/b = a/(-b) = -(a/b)

  -a/(-b) = a/b

__

<u>Summary</u>: The given expression matches (a) and (b).

_____

<em>Additional comments</em>

Sometimes, when I'm really stuck trying to see if two expressions are equal, I subtract one from the other. If the difference is zero, then I know they are the same. Looking at (b), we could compute ...

  \left(\dfrac{-x-7}{y}\right)-\left(\dfrac{x+7}{-y}\right)=\dfrac{-y(-x-7)-y(x+7)}{-y^2}\\\\=\dfrac{xy+7y-xy-7y}{-y^2}=\dfrac{0}{-y^2}=0

Yet another way to check is to substitute numbers for the variables. It is a good idea to use (at least) one more set of numbers than there are variables, just to make sure you didn't accidentally find a solution where the expressions happen to be equal. We can use (x, y) = (1, 2), (2, 3), and (3, 5) for example.

The given expression evaluates to (-1-7)/2 = -4, (-2-7)/3 = -3, and (-3-7)/5 = -2.

(a) evaluates to -(1+7)/2 = -4, -(2+7)/3 = -3, -(3+7)/5 = -2, same as given

(b) evaluates to (1+7)/-2 = -4, (2+7)/-3 = -3, (3+7)/-5 = -2, same as given

(c) evaluates to (-1-7)/-2 = 4, different from given

3 0
3 years ago
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