<span>I believe you use the exponential distribution to find the probability of success (say "p"). Then, you use the Geometric(p) distribution using the "p" you calculated from the exponential as your success probability. Also, in b), you use a negative binomial (which is really just a generalized geometric distribution).
</span><span>Part c) Find the probability to 2 decimal places that the first success occurs in an odd-numbered observation. That is, the first success occurs in the 1st or 3rd or 5th or 7th (and so on) observation.</span>
I would do this by first listing the multiples of 6 until I start to see a pattern with the one's digit.
6x0=0
6x1=6
6x2=12
6x3=18
6x4=24
6x5=30
6x6=36
6x7=42
6x8=48
...
The digits in bold are the one's digits so those are the only ones we really care about. If you list just them it looks like: 0,6,2,8,4,0,6,2,8
Notice how the first set of 5 numbers seems as though it repeats in the 6th, 7th, and 8th numbers. This probably means the pattern continues infinitely so the first 5 numbers are all the one's digits that can come from multiples of 6. Thus your answer is: 0,6,2,8,or 4
Answer:
Step-by-step explanation:
Deepak charges for each Job = $30
An additional charges for working each hour = $15
Let x be the number of hours he worked for each job.
So,additional charges for working x hours = 15 x
So,he earns in total at each job =
We are also given that He only accepts jobs if he will earn at least $90 the job.
This means he must earn $90 or more than that .
So, the inequality becomes:
Hence an inequality to determine x, the number of hours he must work during each job in order to accomplish this is
Step-by-step explanation:
The answer to this question is 39.6.