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3 years ago

How many grams are in 1.3 x 1024 atoms of hydrogen?

Chemistry

1 answer:

olga2289 [7]3 years ago

7 0

Answer: 4.32g

Explanation:

MM of H2 = 1 x 2 = 2g/mol

2g of H2 contains 6.02x10^23 atoms.

Therefore Xg of H2 will contain 1.3 x 1024 atoms i.e

Xg of H2 = (2 x 1.3 x 1024) / 6.02x10^23 = 4.32g

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A _________________ is the path of energy transfer from producer to consumers.

Verizon [17]

Answer: Food chain

Explanation: none

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3 years ago

Ag2S + Al(s) = Al2S3 + Ag(s) (unbalanced)

Dovator [93]

Answer:

1. 0.97 V

2. $Al_(_s_)/Al^+^3~_(_a_q_)~//~Ag^+~_(_a_q_)/Ag_(_s_)$

Explanation:

In this case, we can start with the half-reactions:

$Ag^+~_(_a_q_)->~Ag_(_s_)$

$Al_(_s_)~->~Al^+^3~_(_a_q_)$

With this in mind we can add the electrons:

$Ag^+~_(_a_q_)+~e^-~->~Ag_(_s_)$ Reduction

$Al_(_s_)~->~Al^+^3~_(_a_q_)+~3e^-~$ Oxidation

The reduction potential values for each half-reaction are:

$Ag_2S~+~e^-~->~Ag_(_s_)~+~S^-^2~_(_a_q_)$ - 0.69 V

$Al^+^3~_(_a_q_)+~2e^-~->~Al_(_s_)$ -1.66 V

In the aluminum half-reaction, we have an oxidation reaction, therefore we have to flip the reduction potential value:

$Al_(_s_)~->~Al^+^3~+~2e^-~$ +1.66 V

Finally, to calculate the overall potential we have to add the two values:

1.66 V - 0.69 V = 0.97 V

For the second question, we have to keep in mind that in the cell notation we put the anode (the oxidation half-reaction) in the left and the cathode (the reduction half-reaction) in the right. Additionally, we have to use "//" for the salt bridge, therefore:

$Al_(_s_)/Al^+^3~_(_a_q_)~//~Ag^+~_(_a_q_)/~Ag_(_s_)$

I hope it helps!

3 0

4 years ago

Need help! Don’t understand

shtirl [24]

Bro honestly I don’t understand either

8 0

3 years ago

How do you know if a compound will dissociate or ionize in water?

Ivenika [448]

when an ionic or covalent compound is dissolved in water they break apart into ions through process called dissociation ..the ions get attracted by the water molecules and hence they carry polar charges ..and if there is a conduction of electricity. .then we get to know that a compound is dissociated ..

HOPE IT IS HELPFUL

4 0

3 years ago

A solution with a ph of 4 has _________ the concentration of h+ present compared to a solution with a ph of 5.

Marina CMI [18]

A solution with a pH of 4 has ten times the concentration of H⁺ present compared to a solution with a pH of 5.
pH is a numeric scale for the acidity or basicity of an aqueous solution. It is the negative of the base 10 logarithm of the molar concentration of hydrogen ions.
[H⁺] = 10∧-pH.
pH = 4 → [H⁺]₁ = 10⁻⁴ M = 0,0001 M.
pH = 5 → [H⁺]₂ = 10⁻⁵ M = 0,00001 M.
[H⁺]₁ / [H⁺]₂ = 0,0001 M / 0,00001 M.
[H⁺]₁ / [H⁺]₂ = 10.

7 0

3 years ago