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nataly862011 [7]
3 years ago
5

What salt is produced in each of the following neutralization reactions? HNO3(aq)+KOH(aq)→H2O(l)+? HNO3(aq)+Ca(OH)2(aq)→H2O(l)+?

HCl(aq)+Ca(OH)2(aq)→H2O(l)+? HCl(aq)+KOH(aq)→H2O(l)+?
Chemistry
1 answer:
Igoryamba3 years ago
5 0

Answer:

1. KNO3

2. Ca(NO3)2

3. CaCl2

4. KCl

Explanation:

In each of the neutralization reactions, the H from one of the reactant(acid) will combine with the OH from the other reactant (base) to form water while the other elements combine to give the salt as shown below:

1. HNO3 + KOH → H2O + KNO3

The salt produced is KNO3

2. 2HNO3 + Ca(OH)2 → 2H2O + Ca(NO3)2

The salt produced is Ca(NO3)2

3. 2HCl +Ca(OH)2 → 2H2O + CaCl2

The salt produced is CaCl2

4. HCl +KOH → H2O + KCl

The salt produced is KCl

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a 0.1 kg slinky sits at the top of a staircase with 14 J of potential energy. How high is the staircase?
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Answer: The staircase is 14.28 m high.

Explanation:

Given : Mass = 0.1 kg

Potential energy = 14 J

Potential energy is the energy occupied by the position of a substance. Therefore, formula for potential energy is as follows.

P.E = mgh

where,

m = mass

g = gravitational energy = 9.8 m/s^{2}

h = height of object

Substitute the values into above formula as follows.

P.E = m \times g \times h\\14 J = 0.1 kg \times 9.8 m/s^{2} \times h\\h = \frac{14 J}{0.1 kg \times 9.8 m/s^{2}}\\= \frac{14 J}{0.98 m kg/s^{2}}\\= 14.28 Js^{2}/ mkg          (1 J s^{2}/m kg = 1 m)\\= 14.28 m

Thus, we can conclude that the staircase is 14.28 m high.

5 0
3 years ago
How many moles of oxygen are needed to burn 2.7 moles of methyl
QveST [7]

Answer:

3.38 moles of O2.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

4CH2OH + 5O2 → 4CO2 + 6H2O

From the balanced equation above,

4 moles of CH2OH required 5 moles of O2 for complete combustion.

Finally, we shall determine the number of mole of O2 needed to react with 2.7 moles of CH2OH. This can be obtained as follow:

From the balanced equation above,

4 moles of CH2OH required 5 moles of O2 for complete combustion.

Therefore, 2.7 moles of CH2OH will require = (2.7 × 5)/4 = 3.38 moles of O2 for complete combustion.

Thus, 3.38 moles of O2 is required.

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3 years ago
N an experiment you are asked to react hydrochloric acid with sodium hydroxide. When measuring the volume of the reactants, whic
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Answer:The correct option is, 100 ml Graduated cylinder.

Explanation:Graduated cylinder : It is measuring cylinder that is used to measure the volume of a liquid. It has a narrow cylindrical shape. The marked line drawn on the graduated cylinder shows the amount of liquid that has been measured.

Erlenmeyer flask : It is also called as a conical flask or titration flask. It is a laboratory flask that has flat bottom, a conical body and a cylindrical neck. It is commonly used for the titration.

Beaker : It is a type of laboratory equipment that has cylindrical shape and it is used for the mixing, stirring, and heating of chemicals.

As per question, the graduated cylinders are more accurate and precise than Erlenmeyer flasks and beakers.

8 0
3 years ago
Read 2 more answers
Aqueous sulfuric acid reacts with solid sodium hydroxide to produce aqueous sodium sulfate and liquid water . If of water is pro
MAVERICK [17]

<u>Answer:</u> The percent yield of water is 46.9 %

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

  • <u>For sulfuric acid:</u>

Given mass of sulfuric acid = 72.6 g    (Assuming)

Molar mass of sulfuric acid = 98 g/mol

Putting values in equation 1, we get:

\text{Moles of sulfuric acid}=\frac{72.6g}{98g/mol}=0.741mol

  • <u>For NaOH:</u>

Given mass of NaOH = 77 g      (Assuming)

Molar mass of NaOH = 40 g/mol

Putting values in equation 1, we get:

\text{Moles of NaOH}=\frac{77g}{40g/mol}=1.925mol

The chemical equation for the reaction of sulfuric acid and sodium hydroxide follows:

H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O

By Stoichiometry of the reaction:

1 mole of sulfuric acid reacts with 2 moles of NaOH

0.741 moles of sulfuric acid will react with = \frac{2}{1}\times 0.741=1.482mol of NaOH

As, given amount of NaOH is more than the required amount. So, it is considered as an excess reagent.

Thus, sulfuric acid is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of sulfuric acid reacts with 2 moles of water

0.741 moles of sulfuric acid will react with = \frac{2}{1}\times 0.741=1.482mol of water

  • Now, calculating the mass of water from equation 1, we get:

Molar mass of water = 18 g/mol

Moles of water = 1.482 moles

Putting values in equation 1, we get:

1.482mol=\frac{\text{Mass of water}}{18g/mol}\\\\\text{Mass of water}=(1.482mol\times 18g/mol)=26.67g

  • To calculate the percentage yield of water, we use the equation:

\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

Experimental yield of water = 12.5 g  (Assuming)

Theoretical yield of water = 26.67 g

Putting values in above equation, we get:

\%\text{ yield of water}=\frac{12.5g}{26.67g}\times 100\\\\\% \text{yield of water}=46.9\%

Hence, the percent yield of water is 46.9 %

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3 years ago
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Answer:

PRESSURE is right answer .

Explanation:

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