Question

A balloon originally had a volume of 4.39 l at 44°c and a pressure of 729 torr. to what temperature must the balloon be cooled to reduce its volume to 3.78 l if the pressure is constant

Answer 1

Answer:

Explanation:

p*V/T = constant , but p = constant => V/T = constant

Note: T must be in Kelvin.

V1/T1 = V2/T2

T2 = (V2/V1)* T1

T2 = (3.78/4.39)* (44+273) = 272.95 ≈ 273 K = 0° C

The temperature must be 0° C

Answer 2

The  temperature  of   balloon  that must   be cooled  to  reduce  its volume to  3.78l at   constant   pressure  is  calculated  using the  Charles  law  formula

that  is  V1/T1 =  V2/T2
V1= 4.39 L
T1=  44  +273  = 317K
v2=  3.78L
T2=?
  from the  equation  above  T2 =  V2  x T1/V1
=  3.78  x317/4.39  =  272.95  k  which  is  approximate   273 k
T2  =  273 k  or  O c