Answer:
4 Cases
Step-by-step explanation:
If they bought 3 cases they would only have 864
Answer:
E(X) = 38.9346
Var(X) = 25.588
E(Y) = 38.25
Var(Y) = 26.1875
Step-by-step explanation:
Given - Four buses carrying 153 high school students arrive to Montreal. The buses carry, respectively, 36, 46, 32, and 39 students. One of the students is randomly selected.One of the 4 bus drivers is also randomly selected.
To find - Compute the expectations and variances of X and Y.
Proof -
Let us assume that,
X be The number of students that were on the bus carrying this randomly selected student.
Y denote the number of students on his bus.
Now,
E(X) =
=
= 38.9346
⇒E(X) = 38.9346
Now,
E(Y) =
=
= 38.25
⇒E(Y) = 38.25
Now,
Var(X) =
=
=
= 25.588
⇒Var(X) = 25.588
Now,
Var(Y) = E(Y²) - [E(Y)]²
=
=
= 1489.25 - 1463.0625
= 26.1875
⇒Var(Y) = 26.1875
Answer:
C. 40in
Step-by-step explanation:
so...
576+1024=1600
the missing side = 40in
Answer:
8/32=0.25
Step-by-step explanation:
45/900=110/x
x=(110/45)*900=2200 students
Cristine will find 2200 students when she gets to high school.