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Inessa [10]
3 years ago
9

The first term of an arithmetic sequence is -5, and the tenth term is 13.

Mathematics
1 answer:
Nitella [24]3 years ago
7 0

Answer:

The common difference is 2

Step-by-step explanation:

The formula for an arithmetic sequence is

an = a1+d(n-1)

a1 = -5

a10 = 13

Substituting n=10 a10=13 and a1 =-5

13 = -5 +d (10-1)

13 = -5 +9d

Add 5 to each side

13+5 = -5+5 +9d

18 = 9d

Divide each side by 9

18/9 = 9d/9

2 =d

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2 years ago
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If 1/√a-√b=1/3 and 1/√a+√b=1/2, then find the difference of a and b.​
kow [346]

<u>ANSWER:</u>

If \frac{1}{\sqrt{a}-\sqrt{b}}=\frac{1}{3} and \frac{1}{\sqrt{a}+\sqrt{b}}=\frac{1}{2} then the difference of a and b is 6

<u>SOLUTION:</u>

Given, \frac{1}{\sqrt{a}-\sqrt{b}}=\frac{1}{3} →\sqrt{a}-\sqrt{b}=3 ----- (1)

And \frac{1}{\sqrt{a}+\sqrt{b}}=\frac{1}{2} → \sqrt{a}+\sqrt{b}=2 --- (2)

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Now, add (1) and (2)

\sqrt{a}-\sqrt{b}=3

\sqrt{a}+\sqrt{b}=2

Adding above two equations, we get,

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\begin{array}{l}{2 \sqrt{a}=5} \\\\ {\sqrt{a}=\frac{5}{2}} \\\\ {a=\frac{25}{4}}\end{array}

substitute \sqrt{a} value in (2)

\begin{array}{l}{\frac{5}{2}+\sqrt{b}=2} \\\\ {\sqrt{b}=\frac{2}{\sin \frac{5}{2}}} \\\\ {\sqrt{b}=\frac{4-5}{2}} \\\\ {\sqrt{b}=\frac{-1}{2}} \\\\ {b=\frac{1}{4}}\end{array}

Now, difference of a and b is a – b = \frac{25}{4}-\frac{1}{4}=\frac{24}{4}=6

Hence, the difference of a and b is 6.

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