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Anvisha [2.4K]
3 years ago
10

Can someone do these!!!????

Mathematics
1 answer:
evablogger [386]3 years ago
6 0

Answer:

8/32=0.25

Step-by-step explanation:

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(3x - 2)^5 =(3x - 2)^2
andreyandreev [35.5K]

Answer:

x=3/2,1

Step-by-step explanation:Given

(3x-2)ˆ5-(3x-2)ˆ2=0

(3x-2)ˆ3(3x-2)ˆ2-(3x-2)ˆ2=0

(3x-2)ˆ2{(3x-2)ˆ3-1}=0

(3x-2)ˆ2=0 Or (3x-2)ˆ3-1=0

3x-2=0 Or(3x-2)ˆ3=1

x=3/2 Or 3x-2=1, x=1

4 0
3 years ago
What is the value of x2+9x+20 when x could be -5, -3 or -6
ANTONII [103]

Answer:

Step-by-step explanation:

You should use a ^ to indicate an exponent. x^2 is the same as x².

x² + 9x + 20

Replace the x with (-5).

(-5)² + 9(-5) + 20 = 25-45+20 = 0

Then do the same with x = (-3):

(-3)² + 9(-3) + 20 = 9 - 27 + 20 = 2

You can do x = (-6)

3 0
3 years ago
PLS HELP ME!!!
Mashutka [201]

Answer: 1 cup of sugar; 2 and 1/4 cups of flour; and 1 and 1/2 cups of milk

Step-by-step explanation:

Or simplified; 1 cup of sugar; 9/4 cups of flour; and 3/2 cups of milk

explanation: (do everything times 3)

8 0
3 years ago
What is the volume of 2 1/4 times 1 3/5 times 2 1/3
Arturiano [62]
I recommend the app desmos for problems like this. the answer is 8.4
6 0
3 years ago
Samples of rejuvenated mitochondria are mutated(defective) in 1% ofcases. Suppose 15 samples are studied, and they can be consid
Bezzdna [24]

Answer:

A)0.86

B)0.99

C)6.047E-13

Step-by-step explanation:

Since p = 0.01 and q= 0.99

Number of event n = 15

Using binomial expansion

A) Probability (No samples are mutated) = 15C0 (p)^0 * (q)^15

= 1*(0.01)^0*(0.99)^15 = 0.86

B)Probability (At most one sample is mutated) = 15C0 * p^0 *q^15 + 15C1 * p^1 * q^14 = 1*(0.01)^0*(0.99)^15 + 15C1 * 0.01 * 0.99^14 = 0.86 + 15*0.01*0.8687 = 0.86 + 0.13 = 0.99

C) Probability (More than half the samples are mutated) = 15C8* 0.01^8 * 0.99^7 + 15C9* 0.01^9 * 0.99^6 +15C10* 0.01^10 *0.99^5 + 15C11 * 0.01^11 * 0.99^4 + 15C12 * 0.01^12 * 0.99^3 + 15C13 * 0.01^13 * 0.99^ 2 + 15C14 * 0.01^14 * 0.99^1 + 15C15 * 0.01^15 * 0.99^0

Probability (More than half the samples are mutated) = 6E-13 + 4.71E-15 + 2.86E-17 + 1.31E-19 + 4.41E-22 + 1.03E-24 + 1.49E-27 + 1E-30 = 6.047E-13

3 0
3 years ago
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