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Dovator [93]
3 years ago
5

Help me fast times-a-ticking

Mathematics
2 answers:
d1i1m1o1n [39]3 years ago
8 0

No, because it has a constant rate of change

By looking at this table

The y value changes at a constant multiple of 2

6  4

7  2 (4-2 is a difference of 2)

8  0 (2-0 is a difference of 2)

9  -2 (0-2 is a difference of 2)

This means it is Linear

mash [69]3 years ago
4 0

No, because it has a constant rate of charge.


Rate of change of function: \dfrac{y_2-y_1}{x_2-x_1}

\begin{array}{ccc}6\to4\\7\to2\end{array}\Rightarrow\dfrac{2-4}{7-6}=\dfrac{-2}{1}=-2\\\\\begin{array}{ccc}7\to2\\8\to0\end{array}\Rightarrow\dfrac{0-2}{8-7}=\dfrac{-2}{1}=-2\\\\\begin{array}{ccc}8\to0\\9\to-2\end{array}\Rightarrow\dfrac{-2-0}{9-8}=\dfrac{-2}{1}=-2\\\\


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