Answer:
Step-by-step explanation:
We choose arbitrary values for x and in each case calculate y = 2x + 5.
If x = 0, y = 5; if x = 3, y = 11, and so on.
How? when x = 3, y = 2(3) + 5 = 6 + 5 = 11.
The table, with rows and columns suitable to this problem, would look like:
x y
0 5
3 11
10 25
and so on
The answer is C
I did this test yesterday
Answer:
the answer is 9 b 3 1 5 ghhj
Do you mean LCM
If you just want to know what is the least common multiple of 10 and 60, it is 60
K.E=0.5mv^2
GPE=mgh
The child has both K.E and GPE


g is taken as 9.81