A pharmacist has 40% and 80% of iodine solutions on hand. How many liters of each iodine solution will be required to produce 4 liters of a 50% iodine mixture?
.
Let x = liters of 40% iodine
then
4-x = liters of 80% iodine
Using algebra:
.40x + .80(4-x) = .50(4)
.40x + 3.20-.80x = 2
3.20-.40x = 2
x = 4 liters (40% iodine)
80% iodine:
4-x = 4-4 = 0 liters needed (80% iodine)
Answer:
0.75s
Step-by-step explanation:
The expression would be 0.75s where 0.75 represents the cost of the item after the 25% sale, and s representing the regular cost of the item.
Hope this helps :)
The 100th term would be 505.
The answer to this is 2.
There are a number of proofs to this. Here, we use Euclidean geometry with trigonometry. If we let the center of the circle to be O.
Then, we have the following equations for the angles
CEO = OED = 90
Since, CO = OD because they're radii of the circle, then
ΔCOD is an isosceles triangle and
OCE = ODE
CE + DE = CD
dividing the whole equation by DE
CE/DE + 1 = CD/DE
Using trigonometric functions:
CE = OC cos OCE and
DE = OD cos ODE
Substituting.
OC cos OCE / OD cos ODE + 1 = CD/DE
Since, OCE = ODE,
cos OCE = cos ODE
The equation would be reduced to:
1 + 1 = CD/DE
CD/DE =2
The median is 37 because there are 2 of those numbers. And you have to order them from least to greatest.
