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3 years ago

Please help will give brainlist

Mathematics

1 answer:

uysha [10]3 years ago

4 0

Answer:

The answer is 236.52.

Step-by-step explanation:

First you want to figure out the radius of the semi circle so you take the length of 12 and divide it by 2. Then you want to use the formula for area of a circle 3.14 times radius squared and divide that by 2 and add 12x15 to get your answer.

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Find the greatest common factor and the least common multiple of 16 and 20. The prime factorizations of each number are given.

11111nata11111 [884]

Answer:

i feel like its that one number

Step-by-step explanation:

i found one

4 0

3 years ago

Tree A grows 45 meters in 110 years, and Tree B grows 110 meters in 1,840 years. Which tree grows faster?

Mila [183]

Three A grows 1 meter in 110/45 = 2.44 years;
Three B grows 1 meter in 1840/110 = 16.72 years;
Because 2.44 < 16.73, the tree A grows faster than tree B.

5 0

4 years ago

!!!URGENT!!! ASAP

stellarik [79]

Answer:

i think the first one?

Step-by-step explanation:

i dont think its the second or fourth, so most likely the first one, a line joining points

8 0

3 years ago

Read 2 more answers

Simplify<br><br> − 2 x × 3 x × − x

saveliy_v [14]

-2x * 3x * -x
-6x² * -x
6x³

7 0

4 years ago

4. Automobile policies are separated into two groups: low-risk and high-risk. Actuary Rahul examines low-risk policies, continui

ANTONII [103]

Answer:

Step-by-step explanation:

for n ∈ N

Since Actuary Rahul examines low-risk policies, continuing until a policy with a claim is found and then stopping.

∴ the probability that Actuary Rahul examines exactly n policies

$(0.9)^{n-1}.(0.1)---(1)$

the probability that Actuary Toby examines more than exactly n policies

$(0.8)^n---(2)$

Given that policies are actually independent

∴ the probability that the event (1) and (2) happens simultaneously is

$(0.9)^{n-1}*(0.1)*(0.8)^n$

∴ the probability that Actuary Rahul examines fewer policies than Actuary Toby

$\sum ^\infty _{n=1} (0.9)^{n-1}*(0.1)*(0.8)^n\\\\=(\frac{0.1}{0.9} \sum ^\infty _{n=1}(0.72)^n\\\\=\frac{1}{9} (\frac{0.72}{0.28} )\\\\=\frac{2}{7} \\\\=0.2857$

<h3>the probability that Actuary Rahul examines fewer policies than Actuary Toby is 0.2857</h3>

5 0

3 years ago