One worker<span> produces an average of 84 units per </span>day<span> with a street </span>What is the probability<span> that in any </span>single day worker 1 will outproduce worker 2<span>? A) 0.1141.
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Answer, factory worker productivity<span> is </span>normally distributed<span>. </span>One worker produces<span> an </span>average<span> of 75 </span>units per day<span> with a standar, day with a </span>standard deviation<span> of 20. </span>Another worker produces<span> at an </span>average rate<span> of 65 </span><span>per day.
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Answer:
j-4 is how you show 4 less than a number j
Answer:
B
Step-by-step explanation:
A proportional relationship is represented by linear function with its linear parameter "b" equal to zero. Since b is equal to zero, the line passes through the origin and the function/relation is proportional.
To verify that we divide the y coordinate over the x coordinate we obtain a constant called k, which is the slope.
For instance:
According to this function we can easily check a proportional relationship among its points:
Answer:
4.
Step-by-step explanation:
if the probability it win is 3/5 then 5/5 - 3/5 equals 2/5
which you multiply with 1/2
hope this helps
<u>Answer:</u>
- 6. 6.75
- 7. 27
- 8. 92/17
- 9. 49
<u>Step-by-step explanation:</u>
<u>- Question 6 -</u>
- 9/16 = x/12
- => 16x = 12 x 9
- => 16x = 108
- => x = 6.75
Hence, <u>the value of x in this proportion is 6.75.</u>
<h3>_______________________________</h3>
<u>- Question 7 -</u>
- -3 + x/18 = 12/9
- => -3/18 + x/18 = 4/3
- => x/18 = 4/3 + 1/6
- => x/18 = 8/6 + 1/6
- => x/18 = 9/6
- => x = 9/6 x 18
- => x = 27
Hence, <u>the value of x is 27</u>
<h3>_______________________________</h3>
<u>- Question 8 -</u>
17/15 = 10/2x - 2
=> 17(2x - 2) = 150
=> 34x - 34 = 150
=> 34x = 184
=> x = 184/34
=> x = 92/17
Hence, <u>the value of x is 92/17</u>
<h3>_______________________________</h3>
<u>- Question 9 -</u>
- x - 16/x + 6 = 3/5
- => 5(x - 16) = 3(x + 6)
- => 5x - 80 = 3x + 18
- => 2x = 98
- => x = 49
Hence, <u>the value of x is 49.</u>
<h3>_______________________________</h3>
Hoped this helped.
