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KengaRu [80]
3 years ago
10

I need help with this equation.-2.5+y/6=-16.9

Mathematics
1 answer:
german3 years ago
4 0

Answer:

y= -86.4

Step-by-step explanation:

Not entirely sure but I'm confident in this answer

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The street sign shown is a regular hexagon with side lengths (4x+30) centimeters. The perimeter of the sign is 798 centimeters.
MrRissso [65]

Answer:

25.75

Step-by-step explanation:

A hexagon has 6 sides so

6(4x + 30) = 798

distribute

24x +180 = 798

take away 180 from both sides

24x = 618

divide 24 both sides to get the variable by itself

<u><em>X = 25.75</em></u>

7 0
4 years ago
-3(1-8x-2y) in standard form
madreJ [45]
In standard form, -3(1-8x-2y) is:
DISTRIBUTIVE PROPERTY: 3+24x+6y
ANSWER: 24x+6y-3
7 0
4 years ago
Which sequence is geometric and which is arithmetic?
tekilochka [14]

The table on the left is <u>arithmetic</u>

This is because each term is increasing by the same amount (2) each time.

  • 3+2 = 5
  • 5+2 = 7
  • 7+2 = 9
  • 9+2 = 11

--------------------------------------------

The table on the right is <u>geometric</u>

Why? Because this time we are multiplying each term by the same value (2) to get the next term.

  • 3*2 = 6
  • 6*2 = 12
  • 12*2 = 24
  • 24*2 = 48

Both involve the number 2, but the first table uses addition while the second table uses multiplication.

6 0
3 years ago
Read 2 more answers
A physical therapist wants to determine the difference in the proportion of men and women who participate in regular sustained p
Alekssandra [29.7K]

Using the z-distribution and the formula for the margin of error, it is found that:

a) A sample size of 54 is needed.

b) A sample size of 752 is needed.

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of \alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which z is the z-score that has a p-value of \frac{1+\alpha}{2}.

The margin of error is of:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

90% confidence level, hence\alpha = 0.9, z is the value of Z that has a p-value of \frac{1+0.9}{2} = 0.95, so z = 1.645.

Item a:

The estimate is \pi = 0.213 - 0.195 = 0.018.

The sample size is <u>n for which M = 0.03</u>, hence:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.645\sqrt{\frac{0.018(0.982)}{n}}

0.03\sqrt{n} = 1.645\sqrt{0.018(0.982)}

\sqrt{n} = \frac{1.645\sqrt{0.018(0.982)}}{0.03}

(\sqrt{n})^2 = \left(\frac{1.645\sqrt{0.018(0.982)}}{0.03}\right)^2

n = 53.1

Rounding up, a sample size of 54 is needed.

Item b:

No prior estimate, hence \pi = 0.05

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.645\sqrt{\frac{0.5(0.5)}{n}}

0.03\sqrt{n} = 1.645\sqrt{0.5(0.5)}

\sqrt{n} = \frac{1.645\sqrt{0.5(0.5)}}{0.03}

(\sqrt{n})^2 = \left(\frac{1.645\sqrt{0.5(0.5)}}{0.03}\right)^2

n = 751.7

Rounding up, a sample of 752 should be taken.

A similar problem is given at brainly.com/question/25694087

5 0
3 years ago
Help me I am struggling on this question.
Naily [24]

The top left box is correct

4 0
3 years ago
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