2x squared would be you final answer
We know that imaginary roots always come in pairs, so we already know 4 solutions
-2, 2, 4 + i and a pair of 4 + i
Since imaginary roots always come in pairs we wont have more than 2 imaginary roots, since its a fifth degree root and we can only have 5 roots
So for sure, we will have 3 real roots and 2 imaginary roots
Last option, f(x) has three real roots and two imaginary roots
11
•——-•——•
C D E
9 2
Because the line CE is 11, you will need to subtract it by 9 to find line DE.
11-9=2
To check your work you may add 9 and 2 to find out if it comes out to 11 and it does.
The volume of the right circular cylinder with a radius of 6 m and a height of 9 m is <u>1018 m²</u>.
The volume of a substance is the total space occupied by a three-dimensional object.
The volume of a right circular cylinder with a radius of r units and a height of h units is given by the formula <u>V = πr²h square units</u>.
We are asked to find the volume of the right circular cylinder with a radius of 6 m and a height of 9 m.
Substituting these values in the formula, we get Volume,
V = π(6)²(9) m² = 324π m² = 1017.876 m² ≈ 1018 m².
Therefore, the volume of the right circular cylinder with a radius of 6 m and a height of 9 m is <u>1018 m²</u>.
Learn more about volumes at
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