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Brilliant_brown [7]
3 years ago
5

A system of linear equations in two variables can have _____ solutions. ​

Mathematics
1 answer:
Neporo4naja [7]3 years ago
8 0

Answer:

I would say " zero" to. Sorry if it's wrong

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B) The number of volume of a cylinder is half of its number of the total surface area.
faust18 [17]

Answer:

V=179.6cm^3

Step-by-step explanation:

the volume of a cylinder is given by:

V=\pi r^2h

where r is the radius and h is the height.

and the surface area:

SA=2\pi r^2+2\pi rh

the first term is the area of the circles and the second term is the area of the body.

since "The number of volume of a cylinder is half of its number of the total surface area." we will have that:

V=\frac{1}{2}SA

substitutig the equivalent expressions on each side:

\pi r^2 h = \frac{1}{2} (2\pi r^2+2\pi r h)

and we simplify and solve for the height (since is the value we don't know of the cylinder):

\pi r^2 h = \pi r^2+\pi r h\\\pi r^2h-\pi rh=\pi r^2\\h(\pi r^2-\pi r)=\pi r^2\\h=\pi r^2/(\pi r^2-\pi r)

we substitute the value of the radius r=7cm, and we get:

h=\pi (7cm)^2/(\pi (7cm)^2-\pi (7cm))\\h=153.938/(153.938-21.991)\\h=153.938/131.947\\h=1.1666cm

thus the volume is:

V=\pi r^2h

V=\pi (7cm)^2(1.1666cm)\\V=179.6cm^3

3 0
3 years ago
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Mr. Gurney purchased 3 dozen
DedPeter [7]
If mr Gurney purchased 5 dozen eggs it would be 9.55
8 0
3 years ago
Which are the side lengths of a right triangle? Check all that apply. 3, 14, and StartRoot 205 EndRoot 6, 11, and StartRoot 158
Irina-Kira [14]

It A, C, and E on edge 2020

4 0
3 years ago
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Suppose it is known that 60% of radio listeners at a particular college are smokers. A sample of 500 students from the college i
vladimir1956 [14]

Answer:

The probability that at least 280 of these students are smokers is 0.9664.

Step-by-step explanation:

Let the random variable <em>X</em> be defined as the number of students at a particular college who are smokers

The random variable <em>X</em> follows a Binomial distribution with parameters n = 500 and p = 0.60.

But the sample selected is too large and the probability of success is close to 0.50.

So a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

1. np ≥ 10

2. n(1 - p) ≥ 10

Check the conditions as follows:

 np=500\times 0.60=300>10\\n(1-p)=500\times(1-0.60)=200>10

Thus, a Normal approximation to binomial can be applied.

So,  

X\sim N(\mu=600, \sigma=\sqrt{120})

Compute the probability that at least 280 of these students are smokers as follows:

Apply continuity correction:

P (X ≥ 280) = P (X > 280 + 0.50)

                   = P (X > 280.50)

                   =P(\frac{X-\mu}{\sigma}>\frac{280-300}{\sqrt{120}}\\=P(Z>-1.83)\\=P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that at least 280 of these students are smokers is 0.9664.

8 0
3 years ago
I need help I don’t understand how to do this
hichkok12 [17]

Answer:

your answer is 7 for this problem

4 0
3 years ago
Read 2 more answers
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