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Mila [183]
3 years ago
11

What is the total translational kinetic energy of the air in an empty room that has dimensions 9.00m×14.0m×5.00m if the air is t

reated as an ideal gas at 1.00 atm?
Physics
2 answers:
Lera25 [3.4K]3 years ago
8 0

Answer:3.92475J

Explanation:

ideal gas equation

PV=nrT

P=pressure

V=volume 9*5*14=630m^3

n=mole

Mole=mass/molecular mass

molecular mass of air=28.1g/mol

R=gas constant

T=temperature in kelvin

1.01*10^5*630=(m/28)*8.314j/molK *273K

784959.5677356082g

784.95kg

Kinetic energy=0.5*m*v^2

Velocity of air

0.5*784.95kg*0.1^2

K.E=3.92475J

6

andrew11 [14]3 years ago
5 0

Answer:

9.57 × 10⁷ J

Explanation:

The translational kinetic energy of an ideal gas  is K.E = 3/2nRT. But from ideal gas law, PV = nRT, so

K.E = 3/2PV where pressure of air = 1.00 atm = 1.013 × 10⁵ Pa and V = volume of room = 9.00m × 14.0m × 5.00m = 630 m³

K.E = 3/2PV = 3/2 × 1.013 × 10⁵ Pa × 630 m³ = 9.57 × 10⁷ J

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Answer:

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Explanation:

<u><em>Givens:   </em></u>

It is given that the air starts ionizing when the electric field in the air exceeds a magnitude of 3 x 10^6 N/C, which means that the max electric field can stand without forming a spark is 3 x 10^6 N/C.  

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note:

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