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Mila [183]
3 years ago
11

What is the total translational kinetic energy of the air in an empty room that has dimensions 9.00m×14.0m×5.00m if the air is t

reated as an ideal gas at 1.00 atm?
Physics
2 answers:
Lera25 [3.4K]3 years ago
8 0

Answer:3.92475J

Explanation:

ideal gas equation

PV=nrT

P=pressure

V=volume 9*5*14=630m^3

n=mole

Mole=mass/molecular mass

molecular mass of air=28.1g/mol

R=gas constant

T=temperature in kelvin

1.01*10^5*630=(m/28)*8.314j/molK *273K

784959.5677356082g

784.95kg

Kinetic energy=0.5*m*v^2

Velocity of air

0.5*784.95kg*0.1^2

K.E=3.92475J

6

andrew11 [14]3 years ago
5 0

Answer:

9.57 × 10⁷ J

Explanation:

The translational kinetic energy of an ideal gas  is K.E = 3/2nRT. But from ideal gas law, PV = nRT, so

K.E = 3/2PV where pressure of air = 1.00 atm = 1.013 × 10⁵ Pa and V = volume of room = 9.00m × 14.0m × 5.00m = 630 m³

K.E = 3/2PV = 3/2 × 1.013 × 10⁵ Pa × 630 m³ = 9.57 × 10⁷ J

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Answer:

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3 years ago
An object with a momentum of 1500 kg-m/s directed east is acted upon by an impulse of 100.0 kg-m/s in the same direction. What i
fiasKO [112]

Answer:

The final momentum of the body = 1600 kgm/s

Thus the impulse that acted on the body. = 500 N.s

Explanation:

Momentum: This can be defined as the product of mass and velocity. The S.I unit of momentum is kgm/s. Momentum is a vector quantity.

Mathematically, momentum can be expressed as

M =mv.

Where M = momentum of the object, m = mass of the object, v = velocity of the object.

Impulse acting on the object = Final momentum of the object - initial momentum of the object

I = M₂ - M₁

M₂ = I + M₁......................... Equation 1

Where I = impulse, M₁ and M₂ = Final and initial momentum.

Note:

(i) The momentum and impulse act in the same direction

(ii) impulse is also a vector quantity.

Given: M₁= 1500 kgm/s, I = 100 kgm/s.

Substituting these values into equation 1

M₂ = 1500 + 100

M₂ = 1600 kgm/s.

Thus the final momentum of the body = 1600 kgm/s

14.

I = m(v-u)............................................... Equation 2.

Where I = impulse on the object, m = mass of the object, v = final velocity, u = initial velocity.

Given: m = 100 kg, v = 15 m/s, u = 10 m/s.

I = 100(15-10)

I = 100(5)

I = 500 N.s or 500 kgm/s.

Thus the impulse that acted on the body. = 500 N.s

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4 years ago
A forklift raises a 1,020 N crate 3.50 m up to a shelf. How much work is done by the forklift on the crate?
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8 0
3 years ago
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6) 100 ml of water is initially at 20°C. 30,000 J of heat is added to the water. What is temperature change for the water?
vovangra [49]
<h2>Δt = 71.67 °C</h2>

The temperature change of water is equal to 71.67 °C

<h3>Explanation:</h3>

Given:

Amount of transferred energy = 30,000 K J

Mass of water = 100 ml

Initial temperature = 20°C

To find the change in temperature of water.

Formula for Heat capacity is given by

Q = m×c×Δt ........................................(1)

where:

Q = Heat capacity of the substance (in J)

m=mass of the substance being heated in grams(g)

c = the specific heat of the substance in J/(g.°C)

Δt = Change in temperature (in °C)

Δt = (Final temperature - Initial temperature) = T(f) - T(i)

Q = 30,000 J

Mass of water = m = 100 ml

1 ml = 1 g ................................................(2)

Therefore m = 100 ml = 100 g

Specific heat of water is c = 4.186 J /g.

Δt = ?

Substituting these in equation (1), we get

Q = m×c×Δt

Rearranging the terms for Δt,

Δt = \frac{Q}{m\times c}

Δt = \frac{30,000}{100\times 4.186}  = \frac{30,000}{418.6}= 71.67\°C

Δt = 71.67 °C

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Answer:

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