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2 years ago

8

"1.0 kg mass is attached to the end of a spring. The mass has an amplitude of 0.10 m and vibrates 2.0 times per second. Find its

speed when it passes the equilibrium position."

2 answers:

AleksandrR [38]2 years ago

6 0

Answer:

haha lol

Explanation:

sorry but i dont know this

prisoha [69]2 years ago

4 0

Answer:

1.3m/s

Explanation:

Data given,

Mass,m=1.0kg,

Amplitude,A=0.10m,

Frequency,f=2.0Hz.

From the equation of a simple harmonic motion, the displacement of the object at a given time is define as

$x=Acos\alpha \\$

we can express the velocity by the derivative of the displacement,

Hence

$V=-Awsin\alpha \\$

at equilibrium, the velocity becomes

$V=wA\\w=2\pi f$

Hence if we substitute values we arrive at

$V=2\pi fA\\V=2\pi *2*0.1\\V=1.3m/s$

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If the speed of a wave is 1500m/sec and its frequency is 200 Hz, what is its wavelength

Ray Of Light [21]

Answer:

The wavelength of wave is 7.5 meter.

Given:

Speed of wave = 1500 $\frac{m}{s}$

Frequency of wave = 200 Hz

To find:

Wavelength of wave = ?

Formula used:

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Where $\lambda$ = wavelength of the wave

v = speed of wave

n = frequency of wave

Solution:

Wavelength of wave is given by,

$\lambda = \frac{v}{n}$

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n = frequency of wave

$\lambda = \frac{1500}{200}$

$\lambda$ = 7.5 m

The wavelength of wave is 7.5 meter.

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2 years ago

In certain cases, using both the momentum principle and energy principle to analyze a system is useful, as they each can reveal

kramer

Explanation:

The gravitational force equation is the following:

$F_G = G * \frac{m_1 m_2}{r^2} \\$

Where:

G = Gravitational constant = $6.67408 * 10^{-11} m^3 kg^{-1} s^{-2}$

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8 0

2 years ago

Two blocks of ice, one four times as heavy as the other, are at rest on a frozen lake. A person pushes each block the same dista

qaws [65]

Answer:b

Explanation:

Given

mass of heavy object is 4m

mass of lighter object is m

A person pushes each block with same force F

According to Work Energy theorem Change in kinetic energy of object is equal to Work done by all the object

As launching velocity is same for both the object so heavier mass must possess greater kinetic energy . For same force heavier mass must be pushed 4 times farther than the light block .

$\Delta (K.E.)_H=\frac{1}{2}(4m)v^2$

$\Delta (K.E.)_L=\frac{1}{2}(m)v^2$

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Shkiper50 [21]

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2 years ago

what was the initial temperature is 250 calories reply .1 kg of gold the final temperature of the gold was 175°c ? the specific

weqwewe [10]

Answer:

$115.2^{\circ}C$

Explanation:

When an amount of energy Q is supplied to a substance of mass m, the temperature of the substance increases by $\Delta T$ , according to the equation

$Q=mC_s \Delta T$

where $C_s$ is the specific heat capacity of the substance.

In this problem, we have:

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Solving for $\Delta T$ , we find the change in temperature

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And since the final temperature was

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The initial temperature was

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3 0

2 years ago