Question

"1.0 kg mass is attached to the end of a spring. The mass has an amplitude of 0.10 m and vibrates 2.0 times per second. Find its speed when it passes the equilibrium position."

Answer 1

Answer:

haha lol

Explanation:

sorry but i dont know this

Answer 2

Answer:

1.3m/s

Explanation:

Data given,

Mass,m=1.0kg,

Amplitude,A=0.10m,

Frequency,f=2.0Hz.

From the equation of a simple harmonic motion, the displacement of the object at a given time is define as

$x=Acos\alpha$

we can express the velocity by the derivative of the displacement,

Hence

$V=-Awsin\alpha$

at equilibrium, the velocity becomes

$V=wA\\w=2\pi f$

Hence if we substitute values we arrive at

$V=2\pi fA\\V=2\pi *2*0.1\\V=1.3m/s$