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miss Akunina [59]
2 years ago
15

Ella is 12.537 miles from her house which shows the value of 12.537 rounded to the nearest tenth and nearest hundredths F 12.6,

12.54 G 12.5, 12.54 H.13.0, 12.53 J 12.5, 12.53
Mathematics
1 answer:
ratelena [41]2 years ago
7 0

Answer:

12.5 is to the nearest tenth

12.54 is to the nearest hundredth

Step-by-step explanation:

12.537

The first number after the decimal is the tenths place

we look at the number after it to determine whether to round up or down

12.53  the 3 is less than 5 so we leave it alone

13.5 is rounded to the nearest tenth

The second number after the decimal is the hundrdeths place

we look at the number after it to determine whether to round up or down

12.537  the 7 is greather than or equal to 5 so we round up

13.537  is rounded becomes 13.54

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C

Step-by-step explanation:

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Whats the missing varible for the following questions ​
marta [7]

Answers + Explanation:

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x + 7 - 7 = 10 - 7

x = 3

2. Use the same strategy:

x - 8 = -5

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Which coordinates , are shared by The Triangle and the rectangle
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3 years ago
Estimate the perimeter of the figure to the nearest whole number.
Paha777 [63]

Answer:

The perimeter (to the nearest integer) is 9.

Step-by-step explanation:

The upper half of this figure is a triangle with height 3 and base 6.  If we divide this vertically we get two congruent triangles of height 3 and base 3.  Using the Pythagorean Theorem we find the length of the diagonal of one of these small triangles:  (diagonal)^2 = 3^2 + 3^2, or (diagonal)^2 = 2*3^2.

Therefore the diagonal length is (diagonal) = 3√2, and thus the total length of the uppermost two sides of this figure is 6√2.

The lower half of the figure has the shape of a trapezoid.  Its base is 4.  Both to the left and to the right of the vertical centerline of this trapezoid is a triangle of base 1 and height 3; we need to find the length of the diagonal of one such triangle.  Using the Pythagorean Theorem, we get

(diagonal)^2 = 1^2 + 3^2, or 1 + 9, or 10.  Thus, the length of each diagonal is √10, and so two diagonals comes to 2√10.

Then the perimeter consists of the sum 2√10 + 4 + 6√2.

which, when done on a calculator, comes to 9.48.  We must round this off to the nearest whole number, obtaining the final result 9.

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