(fg)(x)=f(g(x))=4(g(x))²-5=4(x+3)²-5=4x²+24x+31
I can't tell if that is a question but I will answer it anyway:
An exterior of a shape is the lengths and angles outside of the shape.
An interior are the lengths and angles inside a shape.
Hope this helps.
The answer is <span>A)(13, 8).
Distance I to F is: yf - yi = -1 - (-4) = -1 + 4 = 3
Distance D to A is: ya - yd = 8 - 2 = 6
</span>Distance D to A : Distance I to F = 6 : 3<span>
6 : 3 = 2, so scale factor is 2.
Among all choices, we see that the y point of another corner is 8, so we need to find x point.
Distance I to H is: xh - xi = -2 - (-7) = -2 + 7 = 5
Distance A to x corner is: x - xa = x - 3
Since </span>Distance I to H is 5, and scale factor is 2, we have:
Distance A to x corner : Distance I to H = 2
Distance A to x corner = 2 * Distance I to H = 2 * 5 = 10
Distance A to x corner is: xa - x = x - 3 = 10
x - 3 = 10
x = 10 + 3
x = 13
Answer:
3 option is correct
Step-by-step explanation:
because all the domains and ranges calculation matches in eqn 3
60/100 we not read by the third and fifth grade
