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-Dominant- [34]
2 years ago
8

Are the two triangles below similar?

Mathematics
1 answer:
sammy [17]2 years ago
3 0

Answer:

C

Step-by-step explanation:

Yes <em>because</em><em> </em><em>there</em><em> </em><em>are</em><em> </em><em>two</em><em> </em><em>pairs</em><em> </em><em>of</em><em> </em><em>congruent</em><em> </em><em>corresponding</em><em> </em><em>angles</em><em>.</em>

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Consider the figure below. Line FG is parallel to line JK.
Svet_ta [14]

Answer:

A. a = 10

B. m<FNT = 120°

C. m<KTU = 60°

Step-by-step explanation:

A. (7a + 50)° and (14a - 20)° are corresponding angles. Therefore:

(7a + 50)° = (14a - 20)°

Use this equation to find the value of a

7a + 50 = 14a - 20

Combine like terms

7a - 14a = - 50 - 20

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Divide both sides by -7

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B. m<FNT = (14a - 20)° (alternate interior angles are congruent)

Plug in the value of a

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C. m<KTU + (14a - 20)° = 180° (linear pair)

Plug in the value of a

m<KTU + 14(10) - 20 = 180

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m<KTU + 120 - 120 = 180 - 120

m<KTU = 60°

6 0
3 years ago
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