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3 years ago

Find the 7th term of a geometric sequence with t1=5 and r = -2.

Mathematics

1 answer:

Shtirlitz [24]3 years ago

4 0

An=Asub1(r)n-¹
=5(-2)7-¹
=5(64)
A7=320

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3+4 40+3 30+4 which of these is another way to write

zhuklara [117]

(3+4) (40+3) (30+4)
= 7 + 47 + 34
= (7+47) +35
= 54 + 35
= 89

8 0

3 years ago

Read 2 more answers

Given the position of the particle, what the position(s) of the particle when it’s at rest

choli [55]

The position function of a particle is given by:

$X\mleft(t\mright)=\frac{2}{3}t^3-\frac{9}{2}t^2-18t$

The velocity function is the derivative of the position:

$\begin{gathered} V(t)=\frac{2}{3}(3t^2)-\frac{9}{2}(2t)-18 \\ \text{Simplifying:} \\ V(t)=2t^2-9t-18 \end{gathered}$

The particle will be at rest when the velocity is 0, thus we solve the equation:

$2t^2-9t-18=0$

The coefficients of this equation are: a = 2, b = -9, c = -18

Solve by using the formula:

$t=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

Substituting:

$\begin{gathered} t=\frac{9\pm\sqrt[]{81-4(2)(-18)}}{2(2)} \\ t=\frac{9\pm\sqrt[]{81+144}}{4} \\ t=\frac{9\pm\sqrt[]{225}}{4} \\ t=\frac{9\pm15}{4} \end{gathered}$

We have two possible answers:

$\begin{gathered} t=\frac{9+15}{4}=6 \\ t=\frac{9-15}{4}=-\frac{3}{2} \end{gathered}$

We only accept the positive answer because the time cannot be negative.

Now calculate the position for t = 6:

$undefined$

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1 year ago

To take a taxi, it costs \$3.00$3.00dollar sign, 3, point, 00 plus an additional \$2.00$2.00dollar sign, 2, point, 00 per mile t

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You traveled 8 miles
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3 years ago

Read 2 more answers

How many integers have absolute value equal to 7?

Triss [41]

Only two integers i think, 7 and -7

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3 years ago

-6-5[-4-(6+12)]+(-5)

Luden [163]

Answer:

Step-by-step explanation:

-6-5[-4-(6+12)]+(-5)

Following PEMDAS

We work the parentheses from the inside out

-6-5[-4-(18)]+(-5)

-6-5[-22]+(-5)

Now we multiply

-6+110 -5

Now we add and subtract from left to right

104 -5

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3 years ago