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s2008m [1.1K]
3 years ago
13

Find the 7th term of a geometric sequence with t1=5 and r = -2.

Mathematics
1 answer:
Shtirlitz [24]3 years ago
4 0
An=Asub1(r)n-¹
=5(-2)7-¹
=5(64)
A7=320
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Given y = alog(x + c) + d. What would happen to the graph if you changed the value of d? Describe both positive and negative
MariettaO [177]

Answer: A

Step-by-step explanation:

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6 0
3 years ago
Jillian worked her 40 regular hours last week, plus 2 overtime hours at a time-and-a-half rate. Her gross pay was $516. What was
Effectus [21]

Its hourly rate of Jillian is 12 hours.

Here we have to find the hourly rate.

Let h be the hourly rate. As it is given that overtime is a time and a half rate.

So the overtime hour is 1.5h.

The total amount Jillian get is $516.

So from this, we get an equation:

40h + 2(1.5h) = 516

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7 0
1 year ago
Find the average rate of change for the given function from x = −2 to x = 1. Graph of f of x equals x minus 5
Nataliya [291]
Average rate of change=slope

f(x)=x-5
f(x) could be subsitututed  with y so
y=x-5
this is in y=mx+b form where m=slope and b=y-intercept
y=1x-5
slope=1
average rate of change=1/1
if x=-2 then
y=-2-5
y=-7

if x=1 then
y=1-5
y=-4


the graph of y=x-5 is included in the attachment

3 0
3 years ago
Read 2 more answers
Kee’s catering charges $100 to cater a party for 15 people and $12 for each additional person. What is the constant rate of chan
Natasha2012 [34]
The cost for a party here is the base fee, plus charges for any additional guests.

So we know for a 15-person party, the price is going to be $100. That's a flat (constant) cost.

We know that for each additional person, we add $12. So for x more people, the cost is $12x.

Since 100 is constant here, we make that our y-intercept. Even with no additional guests, the cost is still $100.

We add to write y=12x+100. 12 is the constant rate of change (slope).
6 0
3 years ago
What is the sum of the first eight terms of a geometric series whose first term is 3 and whose common ratio is 1/2?
ladessa [460]
\bf \qquad \qquad \textit{sum of a finite geometric sequence}\\\\
S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
r=\textit{common ratio}\\
----------\\
a_1=3\\
r=\frac{1}{2}\\
n=8
\end{cases}

\bf S_8=3\left( \cfrac{1-\left( \frac{1}{2} \right)^8}{1-\frac{1}{2}} \right)\implies 
S_8=3\left( \cfrac{1-\frac{1^8}{2^8}}{1-\frac{1}{2}} \right)
\\\\\\
S_8=3\left( \cfrac{1-\frac{1}{256}}{\frac{1}{2}} \right)\implies S_8=3\left( \cfrac{\frac{255}{256}}{\frac{1}{2}} \right)\implies S_8=3\left( \cfrac{255}{256}\cdot \cfrac{2}{1} \right)
\\\\\\
S_8=3\left( \cfrac{255}{128} \right)\implies S_8=\cfrac{765}{128}
3 0
3 years ago
Read 2 more answers
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