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fiasKO [112]
3 years ago
11

Which of the following is a vapor? steamhidrógen oxygen helium​

Chemistry
1 answer:
Scrat [10]3 years ago
7 0
Helium bc when u vape it goes into it lungs but also bringing helium at the same time.
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2. Extract the relevant information from the question: NaOH V = 30 mL , M = 0.10 M HCl V = 25.0 mL, M = ?
Andrei [34K]

Answer:

0.12M

Explanation:

A balanced equation for the reaction will go a great deal in obtaining our desired result. So, let us write a balanced equation for the reaction

HCl + NaOH —> NaCl + H2O

From the above equation,

nA (mole of the acid) = 1

nB (mole of the base) = 1

Data obtained from the question include:

Vb (volume of the base) = 30mL

Mb (Molarity of the base) = 0.1M

Va (volume of the acid) = 25mL

Ma (Molarity of the acid) =?

The molarity of the acid can be obtained as follow:

MaVa/MbVb = nA/nB

Ma x 25/ 0.1 x 30 = 1

Cross multiply to express in linear form

Ma x 25 = 0.1 x 30

Divide both side by 25

Ma = (0.1 x 30) / 25

Ma = 0.12M

The molarity of the acid is 0.12M

5 0
3 years ago
Please help I don’t know if my answer is right!!
Temka [501]

Answer:

neutralization reaction! Aka: option C!

HOPE THIS HELPS! :)

Explanation:

8 0
3 years ago
A solution contains 0.60 mg/ml mn2+. what minimum mass of kio4 must me added to 5.00 ml of the solution in order to completely o
azamat
The given solution of Mn²⁺ is 0.60 mg/mL.
Hence mass of Mn²⁺ in 5 mL of solution = 0.60 mg/mL x 5 mL = 3 mg

Molar mass of Mn = 54.9 g/mol
Hence, moles of Mn²⁺ = 3 x 10⁻³ g / 54.9 g/mol = 5.46 x 10⁻⁵ mol

The balanced equation for the reaction is,
2Mn²⁺ + 5KIO₄ + 3H₂O → 2MnO₄⁻ + 5KIO₃ + 6H⁺

The stoichiometric ratio between Mn²⁺ and KIO₄ is 2 : 5

Hence, moles of KIO₄ reacted = 5.46 x 10⁻⁵ mol x (5 / 2)
                                                 = 13.65 x 10⁻⁵ mol
Molar mass of KIO₄ = 230 g/mol

Hence needed mass of KIO₄ = 13.65 x 10⁻⁵ mol x 230 g/mol
                                               = 0.031395 g
                                               = 31.395 mg
                                               ≈ 31.4 mg
5 0
3 years ago
Red light has a wavelength of about 6.5 x 10-7m. Find its frequency. Show all work.
ozzi
For this problem we use the wave equation. It is expressed as the speed (c) is equal to the product of frequency (f) and wavelength (v).

c = v x f

We know the wavelength of the an red light which is 6.5 x 10^-7 m. Now, we solve for the wavelength of the unknown wave to see the relation between the two waves.

2.998 X 10^8 = 5.3 X 10^15 X v
v = 2.998 X 10^8 / (5.3 X 10^15) = 5.657 X 10^-8 m

Therefore, the wavelength of the unknown wave is less than the wavelength of the red light.
3 0
3 years ago
How many atoms of hydrogen are in 0.56 mol of (NH4)2SO4
BabaBlast [244]
<h2>Answer:2.7\times 10^{24} atoms</h2>

Explanation:

The given formula of the compound is (NH_{4})_{2}SO{4}

The formula says

Every mole of (NH_{4})_{2}SO{4} contains 8 moles of atoms of hydrogen.

Given that number of moles of compound is 0.56

So,the number of moles of hydrogen atoms present is 0.56\times 8=4.48

Since each mole has 6.022\times 10^{23} atoms,

4.48 moles has 4.48\times 6.022\times 10^{23}=2.7\times 10^{24} atoms.

7 0
3 years ago
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