Question

In order to produce CO2, a student put a sample of calcium carbonate in a flask and added hydrochloric acid using the following equation: Ca(CO3) + HCl → H2O + CO2 + CaCl2 The student finds the mass of CO2 generated to be 100 g. If the student began with 200 g of HCl and there was ample CaCO3 left unreacted, what was the percent yield?

Answer 1

Answer:

82.9% Is the percent yield

Explanation:

First, we need to balance the equation.

Ca(CO3) + 2HCl → H2O + CO2 + CaCl2

Since the problem tells you that the excess reactant is Ca(CO3), we just need to Stoichiometry to solve for the theoretical yield.

$\frac{200g HCl}{1}$ x $\frac{1 mole HCl}{36.46gHCl}$ x $\frac{1 mol CO2}{2molHCl}$ x $\frac{44.01CO2}{1molCO2}$ =120.707 g (theoretical yield)

Take your actual yield of 100g, divide that by 120.707, then multiply that decimical by 100.