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Inga [223]
3 years ago
9

write a real world problem that involves determining the distance between two points on a coordinate plane that have the same x

coordinate
Mathematics
2 answers:
andreyandreev [35.5K]3 years ago
4 0

Answer: sir or ms your anwser would be C 98. hope this helps ;)

Step-by-step explanation:

Mkey [24]3 years ago
3 0
A group of students are doing a project where they make a rocket from bottles. The students all make their separate versions of the bottles. When it is time to launch their rockets, some rockets go higher than other rockets. Student A's rocket goes 3 times higher than the second highest rocket. Student B's rocket goes 50 feet into the air. Student C's rocket went a dozen feet higher into the air than Student B's rocket. If Student D's rocket went 200 feet in the air, how much higher did Student D's rocket go compared to Student A's rocket?
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Is the point (4,7) on the line y=x+3
Tcecarenko [31]

Answer:

Yes.

Step-by-step explanation:

To solve this, simply substitute the points into the equation:

7 = 4 + 3

7 = 7

Therefore, (4,7) is on the line.

6 0
3 years ago
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Use the number 145,973 write the name of the period that has the digits 145
Alexeev081 [22]
145,973 Is decimaled in 145.
14.5
1.45
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7 0
3 years ago
Three times the number of polar bears is more than
Ede4ka [16]
I think the answer to this question is b
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3 years ago
Truck a has a flat fee of 35$ and 0.45$ per mile how much does it cost to go 10 milesi​
kompoz [17]

Answer:

39$ and 50 cents

Step-by-step explanation:

because 35 plus 4.5= 39.5

3 0
4 years ago
Prove the Triangle Proportinality Theorem
Xelga [282]

Answer:

Step-by-step explanation:

Given: DE║BC

To prove: \frac{\text{AD}}{\text{DB}}=\frac{\text{AE}}{\text{EC}}

                Statements                           Reasons

1). DE║BC                                   1). Given

2). ∠1 ≅ ∠4, ∠3 ≅ ∠4                2). Corresponding angles theorem

3). ΔADE ~ ΔABC                      3). AA Similarity theorem

4). \frac{\text{AB}}{\text{AD}}=\frac{\text{AC}}{\text{AE}}                                4). Corresponding sides are proportional

5). \frac{\text{AD+DB}}{\text{AD}}=\frac{\text{AE+EC}}{AE}                   5). Segment addition postulate

6). 1+\frac{\text{DB}}{\text{AD}}=1+\frac{\text{EC}}{\text{AE}}                   6). \frac{a+b}{c}=\frac{a}{c}+\frac{b}{c}

7). \frac{\text{DB}}{\text{AD}}=\frac{\text{EC}}{\text{AE}}                                7). Subtract 1 from both sides

8). \frac{\text{AD}}{\text{DB}}=\frac{\text{AE}}{\text{EC}}                               8). Take the reciprocal of both sides

5 0
3 years ago
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