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3 years ago

Please answer both thank

Mathematics

1 answer:

WARRIOR [948]3 years ago

3 0

Answer:

the second one for #4 and the third one for #5

Step-by-step explanation:

4. The sum of x and y is 24, so x+y = 24. The difference is 15, so x-y = 15, or

y-x=15 (they didn't specify which was which). Therefore, A, C, and D are correct, so x = 15-y is the answer (x = 15-y is the same as x+y = 15, which is false).

Matt = 6 apple pies + 4 lemon pies and he got 80 dollars.

Ming = 6 apple pies + 5 lemon pies and he got 94 dollars.

If apple pie is "a" and lemon is "l":

6a + 4l = 80

6a + 5l = 94,

so C is the answer

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In triangle JKL and triangle PQR line JK = PQR line KL equals QR angle K equal angle Q then JKL must be congruent triangle PQR

Bess [88]

Answer - TRUE

Based on the information given above, we can prove that triangle JKL is congruent to triangle PQR based on the SAS postulate. In other words, since two sides (JK and KL) and the included angle (K) of triangle JKR are congruent to two sides (PQ and QR) and the included angle (Q) of triangle PQR, then triangle JKL must be congruent to triangle PQR.

8 0

4 years ago

Read 2 more answers

Parallelogram ABCD has vertices A(-2, -52), B(-4, -52),

Semenov [28]

Answer:

Step-by-step explanation:

8 0

3 years ago

Nina and Jo both ran an 8 km race. Nina took 55 minutes to run the whole race. Jo started the race 3 minutes later than Nina but

grin007 [14]

Answer:

Step-by-step explanation:

First we figure out how fast Nina can run. If Nina can run 8 km in 55 minutes, then her rate is

$\frac{8km}{55min}=.145\frac{km}{min}$ and we can use that in a d = rt table:

d = r * t

Nina .145

Now we can fill in the distance which is 6 for both, since that is the distance where they met:

d = r * t

Nina 6 = .145

Jo 6 =

Now we go to the info given about the time. If Jo started the race 3 minutes after Nina, that means that Nina is running 3 minutes longer than Jo. Filling in the time info:

d = r * t

Nina 6 = .145 * t + 3

Jo 6 = r * t

As you can see, right now we have 2 unknowns in Jo's row. But we don't have to! We will go to Nina's row where the only unknown is time and solve for t. If d = rt, then

6 = .145(t + 3) and

6 = .145t + .435 and

5.55 = .145t so

t = 38.379 minutes. This means that Jo was running 38.379 minutes when she caught up to Nina (it took Nina 3 minutes longer than that to go 6 km since she was already running for 3 minutes when Jo started the race). If Jo's time is 38.379, we can use that in her row for t and solve for r. If d = rt, then

6 = r(38.379) and

r = .16 km/min

Let's check it without the rounding (rounding takes away from the accuracy). If 6 = .145(t + 3) and Nina's rate not rounded is .145454545 and t = 38.37931034, then, rewriting without rounding:

6 should equal .145454545( 38.37931034 + 3)

6 ?=? .145454545(41.37931034)

6 ?=? 6.0 so

Jo's rate is .16 km/min rounded

6 0

3 years ago

10. Rewrite into slope-intercept form 7x + y = 25

ch4aika [34]

To write in slope-intercept form, you first need to get y by itself. To do this, subtract 7x from both sides of the equation.

Doing this gets you: y = 25 - 7x

Now that y is by itself, remember that slope-intercept form looks like this: y = mx + b

So, let's switch the right side.

y = -7x + 25

Slope intercept form is: y = -7x + 25

Rules for y in Slope-Intercept form:

y must be positive

y must be by itself (so, not 2y, or anything with it... just y)

8 0

3 years ago

In parallelogram DEFG, DH = x + 3, HF = 3y, GH = 3x – 3, and HE = 5y + 4. Find the values of x and y.

Ksju [112]

We have that in this case the following equalities are met:
DH = HF
x + 3 = 3y
GH = HE
3x - 3 = 5y + 4
We then have the following system of equations:
x-3y = -3
3x-5y = 7
Resolving the system graphically we obtain the following values:
x = 9
y = 4
Note: see attached image.
Answer:
The values of x and y are:
x = 9, y = 4

4 0

3 years ago

Please answer both thank ​

Please answer both thank