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3 years ago

Match the base to the corresponding height

Mathematics

1 answer:

Black_prince [1.1K]3 years ago

8 0

The are both equal bc you use the graphing method or I was taught that

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Amul is trying to find the volume of the cylinder. What

tatiyna

Answer:

c its the right answer

Step-by-step explanation: i just took it and got it right

7 0

3 years ago

Express the function y(t)= 4 sin 2πt + 15 cos 2πt in terms of (a) a sine term only. (b) Determine the amplitude, the period, the

Bond [772]

Answer:

See the step by step solution

Step-by-step explanation:

Consider a more general case of the form $a\sin(x)+b\cos(x)$ . We want to express it as a sine term only by using the following formula $\sin(\alpha+\beta) = \sin(\alpha)\cos(\beta)+\sin(\beta)\cos(\alpha)$

The trick consists on find a number $\beta \in [0,2\pi]$ such that $\cos(\beta) = a, \sin(\beta)=b$ . But, note that since $\cos^2(\beta)+\sen^2(\beta)=1$ it is most likely that $a^2+b^2neq 1$ . Then, we will use the following equations:

$\cos(\beta) =\frac{a}{\sqrt[]{a^2+b^2}=A,\sin(\beta) =\frac{b}{\sqrt[]{a^2+b^2}=B$

Then, problem turns out to be

$a\sin(x)+b\cos(x)= \sqrt[]{a^2+b^2}(A\sin(x)+B\cos(x)) =\sqrt[]{a^2+b^2}(\sin(x)\cos(\beta)+\sin(\beta)\cos(x))=\sqrt[]{a^2+b^2}\sin(x+\beta)$ ,

where $\beta = \tan^{-1}(\frac{B}{A})= \tan^{-1}(\frac{b}{a}). So, note that the frequency is the same. Then, a) Taking a=4 and b= 15 we have that 4 sin 2πt + 15 cos 2πt= [tex]\sqrt[]{15^2+4^2}\sin(2\pi t + \tan^{-1}\frac{15}{4})$

b) The amplitude is $\sqrt[]{15^2+4^2} = \sqrt[]{241}$ . Since $2\pi rad/s = 1 Hz$ the frequency is 1 Hz. The period is given by \frac{2\pi}{2\pi} = 1.

c) The function's graph is attached

7 0

3 years ago

Read 2 more answers

PLEASE HELP MEH find the equation the line use exact numbers y=___x+____

Virty [35]

7 and 9 so what u do is calculate the graph and done

6 0

2 years ago

Read 2 more answers

YOUR TURN

Karolina [17]

Answer:

The equation is: y = 15·x

Step-by-step explanation:

It is provided that at the Speedy Bike Works, 15 bicycles are produced each hour.

Consider the table below.

Number of Hours: 1 3 6 10

Number of Bicycles Produced: 15 45 90 150

Compute the ratio of number of bicycles produced and number of hours for every data above as follows:

$\text{1 hour}=\frac{15}{1}=15:1\\\\\text{3 hour}=\frac{45}{3}=\frac{15}{1}=15:1\\\\\text{6 hour}=\frac{90}{6}=\frac{15}{1}=15:1\\\\\text{10 hour}=\frac{150}{10}=\frac{15}{1}=15:1$

The ratio of the number of bicycles produced and number of hours is same for every data value.

Thus, the relationship between the number of bicycles produced and number of hours is proportional.

The equation for the relationship is:

y = 15·x

y = number of bicycles produced

x = number of hours

4 0

3 years ago

Use transformations to solve the equation. c • 5 = 30 A. c = 5 B. c = 6 C. c = 150 D. c = 180

zmey [24]

C * 5 = 30

Divide both sides by 5

c = 6

5 0

2 years ago