Calculate the z-score for the given data points in the item using the equation,
z-score = (x - μ) / σ
where x is the data point, μ is the mean, and σ is the standard deviation.
Substituting,
(47.7) z-score = (47.7 - 52.5)/2.4 = -2
This translates to a percentile of 2.28%.
(54.9) z-score = (54.9 - 52.5)/2.4 = 1
This translates to a percentile of 84.13%.
Then, subtract the calculate percentiles to give us the final answer of <em>81.85%.</em>
Thus, 81.85% of the Siberian Husky sled dogs are expected to weigh between 47.7 and 54.9 lbs.
The answer is 170. First you add base one and base two divide by twi the multiply that by the height. 18+22=40 40/2=20 20•8.5=170
C I’m pretty sure it’s that if not shame me
i think it is
a 40 percent chance
or either 4/10 chance hopefully i helped and if i did plz mark as the brainliest
