A. x -13= x+1 (NO SOLUTION)
B. x + 1/2= x - 1/2 (NO SOLUTION)
C. 2(x + 3)=5x + 6 - 3x (TRUE)
D. x - 3 = 2x - 3 - x (TRUE)
E. 3(x - 5) = 2( x - 5) + 2 (TRUE)
I'm no sure what Im supposed to be doing-
But if I'm supposed to determine if true well there you have it
The segment bisector of line JK would be L since it passes through M
How to find JM is that you would have to solve 3x+15=8x+25 to get x and once you find x you just plug it into the equation for JM, 3x+15
3x+15=8x+25 (subtract 8x on both sides)
-5x+15=25 (subtract 15 on both sides)
-5x=10 (Divide on both sides)
x=-2
Plug that in:
3(-2)+15
-6+15
JM=9
Undefined!! i hope this helps
Answer:
Total distance covered: 60x8 = 480
Speed needed to cover distance of 480 km in 6 hrs = 480/6 = 80 km/hr.
initial velocity : 60 km/hr.
Train needs to run faster with speed of 20km per hour to achieve same distance in 6 hrs.
Step-by-step explanation:
