The range of the function shown on the graph (see attachment) is: D. -9 ≤ y ≤ 8.
<h3>What is a range?</h3>
A range can be defined as the set of all real numbers that connects with the elements of a domain. This ultimately implies that, a range refers to the set of all possible output numerical values, which are shown on the y-axis of a graph.
<h3>How to identify the range of this graph?</h3>
The vertical extent of a graph represents all range values and they are always read and written from smaller to larger numerical values, and from the bottom of the graph to the top.
By critically observing the graph shown in the image attached below, we can reasonably infer and logically deduce the following:
Range = [-9, 8]
In interval notation, the range of this graph can be rewritten as -9 ≤ y ≤ 8.
Read more on range here: brainly.com/question/16610662
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<u>Complete Question:</u>
Select the correct answer.
A graph plots two points at (negative 7, 8) and (negative 2, negative 9) on the x y coordinate plane. A diagonal curve connects both points.
What is the range of the function shown on the graph above?
A. -7≤y≤-2
B.-8≤y≤8
C.-2≤y≤-7
D. -9≤y≤8
Answer:
Since there is no value of x that will ever make this a true statement, the solution to the equation above is “no solution”. Be careful that you do not confuse the solution x = 0 with “no solution”. The solution x = 0 means that the value 0 satisfies the equation, so there is a solution.
Step-by-step explanation:
Answer:
-2a -12
Step-by-step explanation:
a minus * a plus is a negative therefore -12
Answer: 130
Step-by-step explanation: multiply 4 and 28 first because of PEMDAS. After you get 112, add 18 and you get 130.
Answer:
It is proved that if
is even the n is even.
Step-by-step explanation:
Given n is any integer.
To show
is even then n is even.
Proving by contrapositive suppose
is odd. Then we need to show n is odd.
Then, letting k is a ny integer,
Now since (2k+1) is odd therefore n is odd.
Conversly let n is odd, then,

since 2k+1 is odd so
is odd.
This proves, if n is even then
is even.