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3 years ago

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A proportional relationship between the number of pounds of cabbage (x) and the price in dollars (y) is graphed, and the ordered

pair (5,2) is on the graphed
line
Part A: What is the price of 1 pound of cabbage? Show your work.
Part B: What does the ordered pair (10,4) on the graph represent? Explain in words.

1 answer:

Marta_Voda [28]3 years ago

5 0

Answer: A. 1 pound of cabbage will cost 40 cents. B. (10,4) means that 10 pounds of cabbage will cost 4 dollars.

Step-by-step explanation:

If it is proportional that means the y value divided by the x value will give you a constant slope.

So using that use the coordinates (5,2) to find the cost of 1 pound of cabbage.

2/5 = 0.4

so you could write the equation y= 0.4x where x is the number of pound.

Part A: y= 0.4(1)

y= $0.40 which means one pound of cabbage will cost 40 cents.

Part B. (10,4) in this case it will means that for 10 pounds of cabbage it will cost $4.

Plot it into the equation and find out

in the coordinates (10,4) 4 is the y and 10 is the x

4= 0.4(10)

4= 4

Which means it true that 10 pounds of cabbage will cost 4 dollars.

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3 years ago

How do you do expanded form in three ways to the number 37,917,545

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You can't write expanded form in three ways, but you can write that number in expanded form AND two other ways, one you just listed.

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3 years ago

Read 2 more answers

Which set of ordered pairs is a function?

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3 years ago

Find the critical values: a. Determine the critical value z????/2 that corresponds to a level of confidence of 87%. (2 pts). b.

larisa86 [58]

Answer:

a) $z_{\alpha/2}=-1.51$ and $z_{\alpha/2}=1.51$

b) $t_{\alpha/2}=-1.89$ and $t_{\alpha/2}=1.89$

c) $t_{\alpha/2}=-2.11$

d) $z_{\alpha/2}=-1.75$ and $z_{\alpha/2}=1.75$

Step-by-step explanation:

Part a

On this case the confidence is 87% or 0.87 so the significance level is $\alpha=1-0.87=0.13$ and $\alpha/2 =0.065$ . On this case we can assume that is a bilateral test or a confidence interval so we will have two critical values.

We need values a,b on the normal standard distribution such that:

$P(Z$ or $P(Z>b)=0.065$ and in order to find it we can use the following code in excel:

"NORM.INV(0.065,0,1)" or "NORM.INV(1-0.065,0,1)", and we see that the critical values $z_{\alpha/2}=-1.51$ and $z_{\alpha/2}=1.51$

Part b

On this case the confidence is 92% or 0.92 so the significance level is $\alpha=1-0.92=0.08$ and $\alpha/2 =0.04$ . On this case we can assume that is a bilateral test or a confidence interval so we will have two critical values.

First we need to calculate the degrees of freedom given by:

$df=n-1=15-1=14$

We need values b,c on the t distribution with 14 degrees of freddom such that:

$P(t_{(14)}$ or $P(t_{(14)}>c)=0.04$ and in order to find it we can use the following code in excel:

"T.INV(0.04,14)" or "T.INV(1-0.04,14)", and we see that the critical values $t_{\alpha/2}=-1.89$ and $t_{\alpha/2}=1.89$

Part c

The significance level is $\alpha=0.025$ and is a left tailed test. On this case we know that is a left tailed test so then we have just one critical value.

First we need to calculate the degrees of freedom given by:

$df=n-1=18-1=17$

We need a value c on the t distribution with 17 degrees of freddom such that:

$P(t_{(17)}$ , and in order to find it we can use the following code in excel:

"T.INV(0.025,17)", and we see that the critical values $t_{\alpha/2}=-2.11$

Part d

The significance level is $\alpha=0.08$ and $\alpha/2 =0.04$ . On this case we know that w ehave a two tailed proportion test, so we will have two critical values.

We need values a,b on the normal standard distribution such that:

$P(Z$ or $P(Z>b)=0.04$ and in order to find it we can use the following code in excel:

"NORM.INV(0.04,0,1)" or "NORM.INV(1-0.04,0,1)", and we see that the critical values $z_{\alpha/2}=-1.75$ and $z_{\alpha/2}=1.75$

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