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erastova [34]
3 years ago
13

A proportional relationship between the number of pounds of cabbage (x) and the price in dollars (y) is graphed, and the ordered

pair (5,2) is on the graphed
line
Part A: What is the price of 1 pound of cabbage? Show your work.
Part B: What does the ordered pair (10,4) on the graph represent? Explain in words.
Mathematics
1 answer:
Marta_Voda [28]3 years ago
5 0

Answer: A. 1 pound of cabbage will cost 40 cents.  B. (10,4) means that 10 pounds of cabbage will cost 4 dollars.

Step-by-step explanation:

If it is proportional that means the y value divided by the x value will give you a constant slope.

So using that use the coordinates (5,2)  to find the cost of 1 pound of cabbage.

2/5 = 0.4

so you could write the equation y= 0.4x  where x is the number of pound.

Part A:     y= 0.4(1)    

                y= $0.40  which means one pound of cabbage will cost 40 cents.

Part B.    (10,4) in this case it will means that for 10 pounds of cabbage it will cost $4.

   Plot it into the equation and find out

 in the coordinates (10,4) 4 is the y and 10 is the x

   4= 0.4(10)

  4= 4  

Which means it true that 10 pounds of cabbage will cost 4 dollars.

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Pls answer also no explanation no brainliest.
soldier1979 [14.2K]

Answer:

i belive the answer is the option c

3 0
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Complete the square to solve the equation below.
sasho [114]
Hello there!

x² + x = 7/4
x² + - 7/4 = 0

Now we gonna use the quadratic formula to find x
a= 1
b=1
c = -1.75

x = -b+/-√b² -4ac all of them divide by 2a
x = -(1)+/-√(1)² - (4)(1)(-1.75) all of them divide by 2(1)
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mezya [45]
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7 0
3 years ago
Find the equation of the line that is perpendicular to y = –2x + 5 and contains the point
ivann1987 [24]

The given equation is: y+2x=5

To find the line perpendicular to it, we interchange coefficients and switch the signs of one coefficient.

The equation to a line perpendicular to it is:

$ 2y-x=c$

where, $c$ is some constant we have determine using the condition given.

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Put the point in our equation:

$2(-1)-(2)=c$

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The final equation is:

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