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Sindrei [870]
3 years ago
9

How do you write 0.16 repeating as a fraction

Mathematics
2 answers:
son4ous [18]3 years ago
7 0
You write it as 1/6 hope that helps x
deff fn [24]3 years ago
5 0

Answer:

4/25

Step-by-step explanation:

........................................

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Please help me!! <br> solve 31 = x + 25.5
serious [3.7K]

Answer:

x = 5.5

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Equality Properties

Step-by-step explanation:

<u>Step 1: Define</u>

31 = x + 25.5

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Subtract 25.5 on both sides:                    5.5 = x
  2. Rewrite:                                                      x = 5.5
6 0
2 years ago
Read 2 more answers
Statistics 4. Hol (a) The average age of 5 students is 9 years. Out of them, the ages of 4 students are 5, 7, 8, and 15 years. W
olga nikolaevna [1]

Answer:

10 years

Step-by-step explanation:

the average or mean value is the sum of all data points divided by the number of data points.

x = the unknown age of the 5th student.

average = 9 = (5 + 7 + 8 + 15 + x)/5

45 = 5 + 7 + 8 + 15 + x = 35 + x

x = 45 - 35 = 10

the 5th student is 10 years old.

6 0
2 years ago
What is 3/4 x 2? I tried getting it, but my teacher said it was wrong
Karolina [17]
3/4 x 2/1 = 6/4

Simplify:

6/4 = 3/2

So, 3/2 or 1.5
7 0
3 years ago
4(8x−1) = 19+32x
Fantom [35]

<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3

Answer:

Let's solve your equation step-by-step.

4 ( 8x − 1 ) = 19 + 32x

Step 1: Simplify both sides of the equation.

4 ( 8x − 1 ) = 19 + 32x

( 4 ) ( 8x ) + ( 4 ) ( −1 ) = 19 + 32x ( Distribute )

32x + −4 = 19 + 32x

32x − 4 = 32x + 19

Step 2: Subtract 32x from both sides.

32x − 4 − 32x = 32x + 19 − 32x

−4 = 19

Step 3: Add 4 to both sides.

−4 + 4 = 19 + 4

0 = 23

Answer:

There are no solutions.

<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3

5 0
2 years ago
Read 2 more answers
Rewrite each of these statements so that negations appear only within predicates (that is, so that no negation is outside a quan
Ghella [55]

Answer:

Follows are the solution to the given point:

Step-by-step explanation:

In point a:

¬∃y∃xP (x, y)  

∀x∀y(>P(x,y))  

In point b:

¬∀x∃yP (x, y)

 ∃x∀y  ¬P(x,y)

In point c:

¬∃y(Q(y) ∧ ∀x¬R(x, y)) \equiv  ∀y(> Q(y) V ∀ ¬ (¬R(x,y)))

∀y(¬Q(Y)) V ∃xR(x,y) )

In point d:

¬∃y(∃xR(x, y) ∨ ∀xS(x, y))  

∀y(∀x>R(x,y)) \wedge ∃x>s(x,y))

In point e:

¬∃y(∀x∃zT (x, y, z) ∨ ∃x∀zU (x, y, z))

∀y(∃x ∀z)>T(x,y,z) \wedge ∀x ∃z> V (x,y,z))  

8 0
3 years ago
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