Question

F(x) = 6x^2+10x-1f(x)=6x

Answer 1

Answer:

Therefore,

1. The value of Discriminant of f(x) is

$Discriminant =\sqrt{124}$

2. f(x) has  Two Distinct Real number zeros.

Step-by-step explanation:

Given:

$f(x)=6x^{2}+10x-1$

To Find:

1 . What is the value of the discriminant of f(x) = ?

2. How many distinct real number zeros does f(x) have = ?

Solution:

For a Quadratic Equation

$ax^{2}+bx+c=0$

The Discriminant is given as

$Discriminant = \sqrt{b^{2}-4ac}$

So on Comparing and substituting we get

a = 6 ; b = 10 ; c = -1

Therefore,

$Discriminant = \sqrt{10^{2}-4\times 6\times -1}=\sqrt{124}$

Now if,

$Discriminant > 0$ .....f(x) has  Two Distinct Real number zeros

here,

$Discriminant =\sqrt{124}$ Which is greater than zero

Hence f(x) has  Two Distinct Real number zeros

Therefore,

1. The value of Discriminant of f(x) is

$Discriminant =\sqrt{124}$

2. f(x) has  Two Distinct Real number zeros.