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Gwar [14]
3 years ago
13

What is 9 plus 5????

Mathematics
2 answers:
sertanlavr [38]3 years ago
7 0

Answer:

14

Step-by-step explanation:

9 10 11 12 13 14

kolezko [41]3 years ago
4 0

Answer:

14!! Sorry Im late!

Step-by-step explanation:

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Five times a number increased by six equals negative two.
melamori03 [73]
To solve this question simply break down the variables and numbers one at a time.

Here the word a number can be used to describe any number so let’s call that a variable x.

Increased would be addition in mathematics.

Next put everything together.

5x + 6 = -2

5x = -8

X = -8/5.

This is the value of x
4 0
3 years ago
one number is 1 less than a second number. twice the second number is 26 more than 4 times the first number. find the two number
BARSIC [14]
Let x= second number
x-1= first number
2x= 4(x-1) + 26
2x= 4x -4 + 26
2x -4x= 22
-2x= 22
(-1)(-2x)=22(-1)
2x= -22
x=-11 (second number)
-11-1= -12 (first number)
6 0
4 years ago
Y = –x + 4
aliina [53]
Y = -x + 4.....so sub in -x + 4 in for y in the other equation

x + 2y = -8
x + 2(-x + 4) = -8
x - 2x + 8 = -8
x - 2x = -8 - 8
-x = -16
x = 16

y = -x + 4
y = -16 + 4
y = - 12

one solution (16,-12)
8 0
3 years ago
Read 2 more answers
A garden patio is covered with grey and yellow slabs
sp2606 [1]

Answer:

ok........

Step-by-step explanation:

5 0
2 years ago
The bulls eye on an archery target has a radius of 3 inches. the entire target has a radius of 9 inches. to the nearest tenth, f
zaharov [31]
Area of a circle = πr²

--------------------------------------------------------
Area of the archery target :
--------------------------------------------------------
Area of the archery target = 9²π

Area of the archery target = 81π

--------------------------------------------------------
Area of the bull's eye :
--------------------------------------------------------
Area of the bull's eye = 3²π

Area of the bull's eye = 9π

--------------------------------------------------------
Area outside the bull's eye :
--------------------------------------------------------
Area of the target outside the bull's eye = 81π - 9π 

Area of the target outside the bullseye =72π or 226.19 in²

--------------------------------------------------------
Answer: 226.19 in²
--------------------------------------------------------
6 0
3 years ago
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