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sveta [45]
3 years ago
8

Solve the equation 6.8x + 9.3 = -9.4 + 3.4 (2-5x)

Mathematics
2 answers:
STatiana [176]3 years ago
7 0

Answer:

x = -.5

Step-by-step explanation:

6.8x + 9.3 = -9.4 + 3.4 (2-5x)

Distribute the 3.4

6.8x + 9.3 = -9.4 + 6.8 - 17x

Combine like terms

6.8x + 9.3 = -2.6 -17x

Add 17x to each side

6.8x+17x + 9.3 = -2.6-17x+17x

23.8x +9.3 = -2.6

Subtract 9.3 from each side

23.8x +9.3-9.3 = -2.6-9.3

23.8x = -11.9

Divide by 23.8

23.8x/23.8 = -11.9/23.8

x = -.5

neonofarm [45]3 years ago
3 0

Answer:

<h2>x = -0.5</h2>

Step-by-step explanation:

6.8x + 9.3 = -9.4 + 3.4 (2-5x)\qquad\text{multiply both sides by 10}\\\\68x+93=-94+34(2-5x)\qquad\text{use distributive property}\\\\68x+93=-94+(34)(2)+(34)(-5x)\\\\68x+93=-94+68-170x\\\\68x+93=-26-170x\qquad\text{subtract 93 from both sides}\\\\68x=-119-170x\qquad\text{add 170x to both sides}\\\\238x=-119\qquad\text{divide both sides by 238}\\\\x=-\dfrac{119}{238}\\\\\boxed{x=-\dfrac{1}{2}}

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3 years ago
Use Lagrange multipliers to find the volume of the largest rectangular box in the first octant with three faces in the coordinat
tensa zangetsu [6.8K]

Answer:

The volume of the largest rectangular box (V) = 81/4

Step-by-step explanation:

<u>Step 1</u>:-

Given volume of the largest rectangular box in the first octant

V = l b h

let (x ,y, z) be the one vertex in the given plane

V = f(x, y, z) = x y z

given plane.   Ф (x, y, z) = x + 9y + 4z = 27 ........(1)

<u>Step( ii):</u>

By using  Lagrange multipliers

Suppose it is required to find the extreme for the function f(x, y, z) subject to the condition Ф (x, y, z) =0

Form Lagrange function F(x, y, z) = f(x, y, z) + λ  Ф (x, y, z) where λ is called the Lagrange multipliers

F(x, y, z) = x y z+ λ ( x + 9y + 4z - 27) ......(2)

Obtain the equations are δ F / δ x = 0

                                  δ f / δ x +λ  δ Ф  / δ x =0

                           ⇒ y z + λ ( 1) = 0

                          ⇒ y z = - λ ......(a)

Obtain the equations are δ F / δ y = 0

                            δ f / δ x +λ  δ Ф  / δ x =0

                        ⇒ x z + λ ( 9) = 0

                        ⇒ \frac{xz}{9} = - λ .......(b)

Obtain the equations are δ F / δ z = 0

                                  δ f / δ x +λ  δ Ф  / δ z =0

                                   x y + λ ( 4) = 0

                                    ⇒ \frac{xy}{4} = - λ .......(c)

<u>Step (iii):-</u>

Equating (a) and (b) equations

we get         y z = \frac{xz}{9}

cancel 'z' value we get  x = 9y  .......(d)

Equating (b) and (c) equations

we get     \frac{xy}{4}  = \frac{xz}{9}

cancel 'x' value on both sides , we get

              4z =9y  ......(e)

substitute (d) (e) values in equation (1)  we get

x + 9y + 4z -27 = 0

9y + 9y + 9y -27 =0

27y -27 =0

<u> y = 1</u>

substitute y =1 in x = 9y

<u>x = 9</u>

substitute y =1 in 4z =9y

<u>z = 9 /4</u>

therefore the dimensions are x =9 , y=1 and z = 9 /4

<u>Conclusion</u>:-

The largest volume of the rectangular box V = x y z

substitute x =9 , y=1 and z = 9 /4

V = 9(1)(9/4) =81/4

The largest volume of the rectangular box (V) = 81/4

Verification :-

Given plane x + 9y + 4z = 27

substitute x =9 , y=1 and z = 9 /4

              9 + 9 + 4(9/4) = 27

           27 =27

so satisfied equation

     

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