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musickatia [10]
3 years ago
10

Chelsea has four hours of free time on Saturday. She would like to spend no more than 2/3 of an hour on each activity. How many

activities can she do during that time?
Mathematics
2 answers:
STatiana [176]3 years ago
8 0

Answer:

6 activities

Use this website : http://williamreid.weebly.com/uploads/5/8/1/4/58144319/szfbcfbxdef.pdf

Step-by-step explanation:

4 ÷ 2/3 = 4 x 3/2 =12/2=6

Korolek [52]3 years ago
4 0

Answer:

6 activities

Step-by-step explanation:

2/3 multiplied by 6 is 12/3, which equals four.This means that she will be able to do 6 activities.

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Given the equation 6(3 + 2x) = 54, which of the following equations are equivalent?
gizmo_the_mogwai [7]

Answer:

answer for this solution is 2,3,4.

8 0
3 years ago
Suppose you pay a dollar to roll two dice. if you roll 5 or a 6 you Get your dollar back +2 more just like it the goal will be t
LiRa [457]

Answer:

(a)$67

(b)You are expected to win 56 Times

(c)You are expected to lose 44 Times

Step-by-step explanation:

The sample space for the event of rolling two dice is presented below

(1,1), (2,1), (3,1), (4,1), (5,1), (6,1)\\(1,2), (2,2), (3,2), (4,2), (5,2), (6,2)\\(1,3), (2,3), (3,3), (4,3), (5,3), (6,3)\\(1,4), (2,4), (3,4), (4,4), (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)

Total number of outcomes =36

The event of rolling a 5 or a 6 are:

(5,1), (6,1)\\ (5,2), (6,2)\\( (5,3), (6,3)\\ (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)

Number of outcomes =20

Therefore:

P(rolling a 5 or a 6)  =\dfrac{20}{36}

The probability distribution of this event is given as follows.

\left|\begin{array}{c|c|c}$Amount Won(x)&-\$1&\$2\\&\\P(x)&\dfrac{16}{36}&\dfrac{20}{36}\end{array}\right|

First, we determine the expected Value of this event.

Expected Value

=(-\$1\times \frac{16}{36})+ (\$2\times \frac{20}{36})\\=\$0.67

Therefore, if the game is played 100 times,

Expected Profit =$0.67 X 100 =$67

If you play the game 100 times, you can expect to win $67.

(b)

Probability of Winning  =\dfrac{20}{36}

If the game is played 100 times

Number of times expected to win

=\dfrac{20}{36} \times 100\\=56$ times

Therefore, number of times expected to loose

= 100-56

=44 times

8 0
4 years ago
What is the nineteenth term in the sequence 7, 10, 13, 16,...? A 64 B 61 C 57 D 19
Over [174]

Answer:

B. 61

Step-by-step explanation:

7, 10, 13, 16...

ok so were starting with 7 and adding 3 every time

im going to do 3 times 19 like as if we started with 3 then im going to add 4

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57 + 4 = 61

the 19th term is 61

8 0
4 years ago
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Vinvika [58]

Answer:

Look in the picture attached

Step-by-step explanation:

x = 2y - 3

8 0
4 years ago
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Which of the following best describes the equation below? 4(x + 6) + 7x = 11x - 24 A. exactly one real solution, x = B. infinite
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infinite real solution(B)

8 0
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