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3 years ago

Solve the following system of equations using the substitution method. x=4 -2y 4x+8y=20

2 answers:

7 0

Sub 4-2y fo x
4(4-2y)+8y=20
distribute
16-8y+8y=20
16=20
false

therefor there is no solution
if we look carefully, the lines are paralell

answer is no solution

iren2701 [21]3 years ago

4 0

Using the substitution method:

{ x = 4 - 2 y
4 x + 8y = 20

Subsititute x = 4 - 2 y

[ 4(4 - 2 y ) + 8y = 20 ]

Refine:

4( 4-2y ) + 8y = 20

16 - 8 y + 8 y = 20

0 = 16 - 20

-4 = 0

-4 = 0

-4 = 0 ( is false , therefore the system of equations has no solution )

hope this helps!

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For what value of x is the rational expression below equal to zero?

pentagon [3]

Answer:

A.-10 should be the answer to the question..

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3 years ago

A pizza chain wants to send codes for $2 off a large pizza to the subscribers of its e-mail list. Each coupon code will have thr

kati45 [8]

Answer:

438,012 ways.

Step-by-step explanation:

We have been given that each coupon code will have three letters followed by two digits. The letters M, N, and O and the digits 1, 3, 5, and 7 will not be used. So, there are 23 letters and 6 digits that will be used.

Since the letters and digits can be repeated, so we will use fundamental principal of counting.

For first place, we can use 23 letters, for 2nd and 3rd place we can use 23 letters.

We can use 6 digits for 1st digit place and 6 digit for 2nd digit place as repetition is allowed.

So we can choose coupon code is following ways:

$23\cdot 23\cdot 23\cdot 6\cdot 6=438012$

Therefore, we can choose coupon codes in 438,012 ways.

3 0

3 years ago

Match each expression in the left column with the correct product in the right column.

lesya692 [45]

Answer:

-6

-6i

Step-by-step explanation:

1) √4 . √-3 . √-3

$\sqrt{4} = 2$

$\sqrt{-3} . \sqrt{-3} = (\sqrt{-3})^2$

$\sqrt{4} . (\sqrt{-3})^2 = 2 \times -3 =$ -6

2) √-4 . √-3 . √-3

$\sqrt{-4} = 2i$ .

Therefore, $\sqrt{-4} . \sqrt{-3} . \sqrt{-3} = 2. \sqrt{-1} \times -3 = 2i \times (-3) =$ - 6i

3) √4 . √3 . √-3

$\sqrt{4} = 2$

$\sqrt{3} . \sqrt{-3} = (\sqrt{3})^2 . \sqrt{-1}$

$\implies 2 \times 3i =$ 6i

4) √4 . √3 . √3

$\sqrt{4} = 2$

$\sqrt{3} . \sqrt{3} = (\sqrt{3})^2 = 3$

Therefore, √4 . √3 . √3 = 2 . 3 = 6

5 0

3 years ago

Find two consecutive even natural number whose product is 168

Oduvanchick [21]

$2n(2n+2)=168\\
4n^2+4n-168=0\\
n^2+n-42=0\\
n^2+7n-6n-42=0\\
n(n+7)-6(n+7(=0\\
(n-6)(n+7)=0\\
n=6 \vee n=-7\\
-7\not \in \mayhbb{N}\\\\
2n=12\\
2n+2=14$

These numbers are 12 and 14.

7 0

3 years ago

2x^2-13x-24 factor the polynomial<br><br> Explain please

vovangra [49]

Answer:

(x - 8)(2x + 3)

Step-by-step explanation:

To factor a polynomial of the form

ax² + bx + c,

follow these steps:

1) Multiply ac together.

2) Find 2 factors of ac that add to b. Call these factors p and q.

3) Break up the middle term of the polynomial into px + qx.

4) Factor by grouping.

Now let's follow the steps above with your problem.

You are given the polynomial

2x² - 13x - 24,

so a = 2, b = -13, and c = -24

1) Find ac.ac is the product 2(-24) = -48

2) Now we need to find 2 factors of -48 that add to b, -13.

I know that 48 = 3 × 16, so if we use -16 and 3 for the two numbers, we have

-16 + 3 = -13

and -16 × 3 = -48.

3) Now we break up the middle term of the polynomial, -13x, into -16x + 3x.

The polynomial is now

2x² - 16x + 3x - 24

4) We factor the polynomial by grouping. To factor by grouping, you factor a common factor out of the first 2 terms and factor out a common factor out of the last two terms.

2x² - 16x + 3x - 24 =

= 2x(x - 8) + 3(x - 8)

We now see the common factor of x - 8, so we factor that out.

= (x - 8)(2x + 3)

Answer: (x - 8)(2x + 3)

8 0

2 years ago