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3 years ago

Find the slope of the line passing through (-3, 4) and (1, -7) URGENT PLEASE HURRY

Mathematics

2 answers:

deff fn [24]3 years ago

5 0

Answer:

$slope=\frac{1-(-3)}{(-7-4)}= -\frac{4}{11}$

Step-by-step explanation:

Formula to calculate slope (m) is given as

$m=\frac{x_{2}- x_{1}}{y_{2}- y_{1}}$

here

$(x_1, y_1)=(-3, 4)$

and

$(x_2, y_2)=(1, -7)$

xeze [42]3 years ago

3 0

Step-by-step explanation:

y=11x-5 or something like that.. I'm not sure on the ending

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15% of what amount is 6?

Nadusha1986 [10]

Hey there!

0.9 is 15% of 6

work:
0.15 x 6 = 0.9

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Kareem correctly answered 85% of the questions on his last math test. If hee missed 6 problems, how many questions were there on

Reil [10]

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2 years ago

An ice cream factory makes 68.8 quarts of ice cream

yaroslaw [1]

ANSWER: 68.8 quarts is 19.7 gallons

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2 years ago

You are jumping off the 12 foot diving board at the municipal pool. You bounce up at 6 feet per second and drop to the water you

NARA [144]

Answer:

When do you hit the water?

1.075 seconds after you jump.

What is your maximum height?

the maximum height is 12.5626 ft

Step-by-step explanation:

The equation:

h(t) = -16*t^2 + 6*t + 12

Is the height as a function of time.

We know that the initial height is the height when t = 0s

h(0s) = 12

and we know that the diving board is 12 foot tall.

Then the zero in h(t)

h(t) = 0

Represents the surface of the water.

When do you hit the water?

Here we just need to find the value of t such that:

h(t) = 0 = -16*t^2 + 6*t + 12

Using the Bhaskara's formula, we get:

$t = \frac{-6 \pm \sqrt{6^2 - 4*(-16)*12} }{2*(-16)} = \frac{-6 \pm 28.4}{-32}$

Then we have two solutions, and we only care for the positive solution (because the negative time happens before the jump, so that solution can be discarded)

The positive solution is:

t = (-6 - 28.4)/-32 = 1.075

So you hit the water 1.075 seconds after you jump.

What is your maximum height?

The height equation is a quadratic equation with a negative leading coefficient, then the maximum of this parabola is at the vertex.

We know that the vertex of a general quadratic:

a*x^2 + b*x + c

is at

x = -b/2a

Then in the case of our equation:

h(t) = -16*t^2 + 6*t + 12

The vertex is at:

t = -6/(2*-16) = 6/32 = 0.1875

Evaluating the height equation in that time will give us the maximum height, which is:

h(0.1875) = -16*(0.1875 )^2 + 6*(0.1875) + 12 = 12.5626

And the height is in feet, then the maximum height is 12.5626 ft

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3 years ago