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Lena [83]
3 years ago
5

prism M and pyramid n have the same base area and the same height. cylinder p and prism Q have the same height and the same base

perimeter. cone z has the same base area as cylinder y but its height is 3 times the height of cylinder y the figures_ and _ have the same volume ​
Mathematics
1 answer:
Katen [24]3 years ago
6 0

Answer:

The volume of cone z has the same base area as cylinder y but its height is 3 times the height of cylinder y have the same volume.

Step-by-step explanation:

The volume of a cylinder having base area 'A' and height 'H' is given by  V = AH, and the volume of a cone having the same base area as the cylinder i.e. A and height 3 times the height of the cylinder i.e. 3H is given by V' = \frac{1}{3} A(3H) = AH.

So, V = V'

Hence, the volume of cone z has the same base area as cylinder y but its height is 3 times the height of cylinder y have the same volume. (Answer)

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Formula to find the missing number Faces:15 vertices:15 edges:?
gtnhenbr [62]

Answer:

Step-by-step explanation:

Euler's formula is

V - E + F = 2

Givens

V = 15

E = 15

F = ?

Solution

15 - 15 + F = 2

F = 2

I'm not sure this makes sense, but it is what the formula gives you.

7 0
3 years ago
I need help with this question
vichka [17]

Answer:

12

step by step explanation:

-22+34=12

8 0
4 years ago
And this problem your multiplying 12 by 6 was 12 called in this math problem
Lynna [10]

To multiply one number ( a multiplicand ) by another ( a multiplier ) means to repeat a multiplicand as an addend times. The result of multiplying is called a product. The operation of multiplication is written as: 12 x 6, or 12 * 6

Multiply 12 by 6

6 is called the Multiplier

12 is called the Multiplicand

72 is called the Product

Therefore, a multiplicand and a multiplier are called factors or multipliers.

Hope that helps!!!! : )

5 0
3 years ago
Fit a quadratic function to these three points: (-2,8)(0,-4),and (4,68)
aev [14]
Given three points
P1(-2,8)
P2(0,-4)
P3(4,68)
We need the quadratic equation that passes through all three points.

Solution:
We first assume the final equation to be
f(x)=ax^2+bx+c .............................(0)

Observations:
1. Points are not symmetric, so cannot find vertex visually.
2. Using the point (0,-4) we substitute x=0 into f(x) to get
f(0)=0+0+c=-4, hence c=-4.
3. We will use the two other points (P1 & P3) to set up a system of two equations to find a and b.
f(-2)=a(-2)^2+b(-2)-4=8 => 4a-2b-4=8.................(1)
f(4)=a(4^2)+b(4)-4=68 =>  16a+4b-4=68.............(2)
4. Solve system
2(1)+(2) => 24a+0b-12=84 => 24a=96 => a=96/24 => a=4 ......(3)
substitute (3) in (2) => 16(4)+4b-4=68 => b=8/4 => b=2  ..........(4)
5. Put values c=-4, a=4, b=2 into equation (0) to get

f(x)=4x^2+2x-4

Check:
f(-2)=4((-2)^2)+2(-2)-4=16-4-4=8
f(0)=0+0-4 = -4
f(4)=4(4^2)+2(4)-4=64+8-4=68
So all consistent, => solution ok.

6 0
4 years ago
A store pays $423 for a crystal vase and marks the price up by 46%. What is the amount of the mark-up?
jek_recluse [69]

Answer:

194.58$

Step-by-step explanation:

Have a great day! :)

6 0
3 years ago
Read 2 more answers
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