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quester [9]
4 years ago
9

The average height of middle school students at Seton Grove School is found to be 5.25 feet. Which sample makes this generalizat

ion valid?
A.
every third basketball player who walks onto the basketball court
B.
an equal number of boys and girls from the track team
OC. every other student who enters the school
D.
every other boy who enters the school

​
Mathematics
2 answers:
Reika [66]4 years ago
7 0

Answer:

C

Step-by-step explanation:

Andre45 [30]4 years ago
4 0

Answer:

B.

an equal number of boys and girls from the track team

Step-by-step explanation:

an equal number of boys and girls from the track team makes the generalization that the average height of middle school students at Seton Grove School is 5.25 feet valid

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In 1992, the moose population in a park was measured to be 4260. By 1996, the population was measured again to be 3660. If the p
masha68 [24]

In 1992, the moose population in a park was measured to be 4260. By 1996, the population was measured again to be 3660. If the population continues to change linearly: A.) Find a formula for the moose population, P , in terms of t , the years since 1990. P ( t ) = B.) What does your model predict the moose population to be in 2008?

<u>Answer:</u>

Model predict the moose population to be in 2008 is 1860

<u>Solution:</u>

Let us consider this problem on graph, taking the x axis to be years since 1990 and y on the graph be the number of moose

We have two points on the graph:  (2, 4260) and (6, 3660)

Using the slope formula we can find the slope :

\mathrm{m}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

m=\frac{(3660-4260)}{(6-2)}

m = -150                                  

Now that we have the slope of the line, we can use the point-slope formula to find the equation for the line as follows:-

\begin{array}{l}{y-y_{1}=m\left(x-x_{1}\right)} \\\\ {y-4260=-150(x-2)} \\\\ {y-4260=-150 x+300} \\\\ {y=-150 x+4560}\end{array}

Since the formula that is being sought is supposed to be interms of P and t, we will replace y with P and x with t

P(t) = -150t + 4560

Number of years from 1990 to 2008 is  

2008 - 1990 = 18

So, population in 2008 will be

P(18) = -150 (18) + 4560

P(18) = -2700 + 4560

P(18) = 1860

Thus the model to predict the moose population in 2008 is found

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