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Sidana [21]
3 years ago
14

A random sample of 20 purchases showed the sample mean of $48.77 and the sample standard deviation s is $17.58. How large is the

margin of error for a 80 % confidence interval for the mean purchases of all customers
Mathematics
1 answer:
laila [671]3 years ago
3 0

Answer:

<h2>$5.03</h2>

Step-by-step explanation:

Given data          

Sample Mean (M):  $48.77  

Sample Size (n): 20

Standard Deviation (σ) :  $17.58

Confidence Level: 80%

 we know that z*-Values for 80% Confidence  Levels is 1.28

the expression for margin of error is given bellow\

MOE= z*σ/√n

We can now substitute into the expression and solve for the MOE as

MOE= 1.28*17.58/√20

MOE= 22.502/4.47

MOE= 22.502/4.47

MOE= 5.03

The margin of error for a 80 % confidence interval is $5.03

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What is the slope intercept of the equation of the line through the given point (0,3) and (-4,-1)
cestrela7 [59]

Answer:

y=x+3

Step-by-step explanation:

1.) Find slope

slope = (-1-3)/(-4-0)

= -4/-4

= 1

2.) Use point slope form

<u>y-y1= m (x-x1) </u>

both x1 and y1 are the points

m is the slope

3.) Plug in the numbers

for the points I chose (0,3) to plug in

y-3= 1 (x1-0)

y-3= x

y= x+3

8 0
3 years ago
Mohamed decided to track the number of leaves on the tree in his backyard each year The first year there were 500 leaves Each ye
svetlana [45]

Answer:

The required recursive formula is

f(n)= 500\times(1.4)^{n-1}\\

Step-by-step explanation:

Mohamed decided to track the number of leaves on the tree in his backyard each year.

The first year there were 500 leaves

Year \: 1 = 500

Each year thereafter the number of leaves was 40% more than the year before so that means

Year \: 2 = 500(1+0.40) = 500\times 1.4\\

For the third year the number of leaves increase 40% than the year before so that means

Year \: 3 = 500\times 1.4(1+0.40) = 500 \times 1.4^{2}\\

Similarly for fourth year,

Year \: 4 = 500\times 1.4^{2}(1+0.40) = 500\times 1.4^{3}\\

So we can clearly see the pattern here

Let f(n) be the number of leaves on the tree in Mohameds back yard in the nth year since he started tracking it then general recursive formula is

f(n)= 500\times(1.4)^{n-1}\\

This is the required recursive formula to find the number of leaves for the nth year.

Bonus:

Lets find out the number of leaves in the 10th year,

f(10)= 500\times(1.4)^{10-1}\\\\f(10)= 500\times(1.4)^{9}\\\\f(10)= 500\times20.66\\\\f(10)= 10330

So there will be 10330 leaves in the 10th year.

3 0
3 years ago
Read 2 more answers
Estephany has a box that is filled with toys. The box has a length of 3.5 feet, a width of 6 feet, and a height of 3 feet. What
Zigmanuir [339]

Answer:

63

Step-by-step explanation:

The formula for volume of a box is length×width×height = volume

So you would multiply  3.5×6×3=63

6 0
2 years ago
Solve this equation for A: A ÷ 2 = 4
Natali5045456 [20]
The answer to the equation is 8
5 0
3 years ago
Read 2 more answers
...im failing please
Taya2010 [7]

Answer:

top row on 9 page; 9) 53/5 10) 26/4 11) 37/4

bottom row on 9 page; 9) 8 and 1/7 10) 6 and 3/4 11) 1 and 1/3

top row on 3 page; 3) 2 and 2/7 4) 5 and 3/4 5) 8 and 1/10

bottom row on 3 page; 3) 4/3 4) 3/2 5) 12/5

top row on 12 page; 12) 21/10 13) 62/6 14) 57/6

bottom row on 12 page; 12) 1 and 9/10 13) 10 and 1/2 14) 3 and 3/8

Step-by-step explanation:

You never specified if these had to be simplified or turned into a fraction, so I just simplified them. That's about it.

I hope this helps :)

7 0
2 years ago
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