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TEA [102]
4 years ago
14

Listed below are amounts​ (in millions of​ dollars) collected from parking meters by a security service company and other compan

ies during similar time periods. Do the limited data listed here show evidence of stealing by the security service​ company's employees? Security Service Company:Security Service Company: 1.41.4 1.81.8 1.61.6 1.71.7 1.51.5 1.51.5 1.71.7 1.61.6 1.51.5 1.61.6 Other Companies:Other Companies: 1.81.8 1.91.9 1.61.6 1.71.7 1.61.6 1.81.8 1.71.7 1.51.5 1.81.8 1.71.7 Find the coefficient of variation for each of the two​ samples, then compare the variation.
Mathematics
1 answer:
dezoksy [38]4 years ago
6 0
Given: Security Service Company:
1.4 1.8 1.6 1.7 1.5 1.5 1.7 1.6 1.5 1.6
Mean: 1.59
Standard Deviation: 0.014333

Other companies: 1.8 1.9 1.6 1.7 1.6 1.8 1.7 1.5 1.8 1.7
Mean: 1.71
Standard deviation: 0.014333

The coefficient of variation for security Service Company:

CV = (Standard Deviation/Mean) * 100.

= (0.14333/1.59) * 100

= 9.01%

The coefficient of variation for other companies:

CV = (Standard Deviation/Mean) * 100.

= (0.014333 / 1.71) * 100

= 8.38%

the limited data listed here show evidence of stealing by the security service company's employees because there is a significant difference in the variation.
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Answer:

The time at which they will all meet at a place together is 350 minutes

Step-by-step explanation:

The time it takes Faiza to cycle the park = 60 seconds

The time it takes Krish to cycle the park = 14 seconds

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Therefore, the time they will all meet at a place together is given by their Lowest Common Multiple as follows;

LCM = 60 × 14 × 25 = 21,000 seconds

Therefore, the time at which they will all meet at a place together in minutes = 21000 seconds/(60)×minute/second = 350 minutes

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3 years ago
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irinina [24]
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3 years ago
Find the missing dimension of the prism. Round your answer to the nearest hundredth.
Nitella [24]

Answer:

x = 6.99in

Step-by-step explanation:

Given

l =2in

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See attachment for prism

Required

Find x

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The base area is calculated as:

Base\ Area= \frac{3\sqrt 3}{2}l^2

This gives:

Base\ Area= \frac{3\sqrt 3}{2} * 2^2

Base\ Area= \frac{3\sqrt 3}{2} * 4

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3 years ago
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